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Kazeer [188]
3 years ago
7

What is the value of x?

Mathematics
1 answer:
olga_2 [115]3 years ago
3 0

Answer:

<x = 20°

Step-by-step explanation:

<x = 1/2(arc UT - arc SV)

<x = 1/2(65° - 25°)

<x = 1/2 (40°)

<x = 20°

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I don't understand linear relationships. Can someone explain how it works
Vesna [10]
Linear relationships can be expressed in a graphical format where the variable and the constant are connected via a straight line or in a mathematical format where the independent variable is multiplied by the slope coefficient, added by a constant, which determines the dependent variable.
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Solve the following quadratic function
Leya [2.2K]

Answer:

x = ± 10

Step-by-step explanation:

to solve the equation let y = 0 , that is

100 - x² = 0 ( add x² to both sides )

100 = x² ( take square root of both sides )

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8 0
2 years ago
Complete the point-slope equation of the line through (2,3 and (7,4). Use exact numbers.
uysha [10]

The point-slope equation of the line is y-3=\frac{1}{5}(x-2)

Step-by-step explanation:

The form of the point-slope equation is y-y_{1}=m(x-x_{1}) , where

  • m is the lope of the line
  • (x_{1},y_{1}) is a point lies on the line

The slope of a line m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where

(x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line

∵ The line through (2 , 3) and (7 , 4)

∴ x_{1} = 2 and x_{2} = 7

∴ y_{1} = 3 and y_{2} = 4

- Substitute these value in the rule of the slope

∵ m=\frac{4-3}{7-2}=\frac{1}{5}

∴ the slope of the line is m=\frac{1}{5}

Let us substitute the value of the slope and the coordinates of point (x_{1},y_{1}) in the form of the equation

∵ y-y_{1}=m(x-x_{1})

∵ x_{1} = 2 and y_{1} = 3

∵ m=\frac{1}{5}

∴ y-3=\frac{1}{5}(x-2)

The point-slope equation of the line is y-3=\frac{1}{5}(x-2)

Learn more:

You can learn more about the linear equation in brainly.com/question/12941985

#LearnwithBrainly

3 0
3 years ago
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629.63*0.1475/12=7.74
6 0
3 years ago
Read 2 more answers
Simplify 6^3/6^2<br> A. 6<br> B. 1 1/2<br> C. 18<br> D. 256
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The answer would be (A) 6
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