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3 years ago

12

A Venn diagram is shown below:

2 answers:

mina [271]3 years ago

6 0

(A ∩ B) means "A intersection B". Your problem statement tells you the intersection contains
{3, 4}

pychu [463]3 years ago

6 0

Answer:

ths is wrong

Step-by-step explanation:

You might be interested in

Which are shown on a balance sheet? Check all that apply.

Olin [163]

Answer:

Assets, liabilities and time period

Step-by-step explanation:

A balance sheet shows the financial affairs of a company as of a particular date.

After financial statements, namely trading, profit and loss account, and profit and loss appropriations accounts are prepared, the profit is transferred to capital account.

The balances shown in each account will be shown in the balance sheet.

Since balance sheet is of a particular date, time period is compulsory to appear in the balance sheet besides assets as of close of business and liabilities will be shown.

So answer is

Assets,liabilities and time period.

3 0

3 years ago

Tell me the answer for each box its on classkick and i can see if its wrong

Licemer1 [7]

Answer:

$19.35

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write twelve and sixteen thousand as a mixed decimal

Jlenok [28]

12.016

hope this helps

8 0

3 years ago

Please help!! Evaluate the piece wise function at x=-4 and x=4.

hodyreva [135]

x = -4, so use the first equation, x^2 = -4^2 = -16

x = 4, use 3rd equation, sqrt(x) = sqrt(4) = 2

4 0

3 years ago

Bob and Anna are planning to meet for lunch at Sally's Restaurant, but they forgot to schedule a time. Bob and Anna are each goi

Viktor [21]

Answer:

The expected cost is $8.75

<em></em>

Step-by-step explanation:

Given

$Time = \{1pm, 2pm, 3pm, 4pm\}$

$C_1 = \$5$ --- If Bob and Anna meet

$C_2 = \$10$ --- If Bob and Anna do not meet

Required

The expected cost of Bob's meal

First, we list out all possible time both Bob and Anna can select

We have:

$(Bob,Anna) = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3)$ $,(3,4),(4,1),(4,2),(4,3),(4,4)\}$

$n(Bob, Anna) = 16$

The outcome of them meeting at the same time is:

$Same\ Time = \{(1,1),(2,2),(3,3),(4,4)\}$

$n(Same\ Time) = 4$

The probability of them meeting at the same time is:

$Pr(Same\ Time) = \frac{n(Same\ Time)}{n(Bob,Anna)}$

$Pr(Same\ Time) = \frac{4}{16}$

$Pr(Same\ Time) = \frac{1}{4}$

The outcome of them not meeting:

$Different = \(Bob,Anna) = \{(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2)$

$,(3,4),(4,1),(4,2),(4,3)\}$

$n(Different) = 12$

The probability of them meeting at the same time is:

$Pr(Different) = \frac{n(Different)}{n(Bob,Anna)}$

$Pr(Different) = \frac{12}{16}$

$Pr(Different) = \frac{3}{4}$

The expected cost is then calculated as:

$Expected = C_1 * P(Same) + C_2 * P(Different)$

$Expected = \$5 * \frac{1}{4} + \$10 * \frac{3}{4}$

$Expected = \frac{\$5}{4} + \frac{\$30}{4}$

Take LCM

$Expected = \frac{\$5+\$30}{4}$

$Expected = \frac{\$35}{4}$

$Expected = \$8.75$

<em>The expected cost is $8.75</em>

4 0

3 years ago