Linear functions have no exponents higher than 1, and a graph that looks like a straight line. non-linear functions have at least one exponent higher than 1, and a graph that isn't a straight line
Answer:

Step-by-step explanation:
We have the cone and the half-sphere.
The formula of a volume of a cone:

r - radius
H - height
We have r = 7cm and H = (22-7)cm=15cm. Substitute:

The formula of a volume of a sphere:

R - radius
Therefore the formula of a volume of a half-sphere:

We have R = 7cm. Substitute:

The volume of the given shape:

Substitute:

444 ÷ 2 = 222
444 ÷ 3 = 148
90 ÷ 2 = 45
90 ÷ 3 = 30
90 ÷ 5 = 18
90 ÷ 10 = 9
45 ÷ 3 = 15
45 ÷ 5 = 9
So 444 can be divided into 2 and 3
90 can be divided into 2, 3, 5, and 10
45 can be divided into 3 and 5
Hope this helps. :)
Answer:
24 munchkins.
Step-by-step explanation:
Let C be the number of chocolate and D be number of glazed donut holes in the original box.
We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:
Upon substituting C's value from equation (2) in equation (1) we will get,
Let us have a common denominator on right side of equation.


Multiplying both sides of our equation by 7, we will get,

Multiplying both sides of our equation by 11, we will get,
Therefore, the total number of Munchkins in original box is 24.