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3 years ago

Help me please Solve the system algebraically using substitution.

Mathematics

1 answer:

cluponka [151]3 years ago

3 0

Answer:

y = 5/3

x = 8/3

Steps:

y = x - 1

2x + y = 7

Substitute y = x-1

(2x + x - 1 = 7)

Simplify: 3x - 1 = 7

Isolate x: 3x - 1 = 7: x=8/3

Plug the valuse of x into the other equation (y = x- 1): y = 8/3 - 1

8/3 - 1 = 5/3

y = 5/3

y = 5/3, x = 8/3

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3 years ago

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4 years ago

Read 2 more answers

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qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

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3 years ago

Which expression is equivalent to 5(9 + 7). I will mark brainliest if you answer. DatGuy323 I like You! Answer please

Virty [35]

Answer: 80

Step-by-step explanation:

$5(9+7)\\\\Parenthesis\\\\5(16)\\\\Multiply\\\\80$

Hope it helps <3

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3 years ago