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Rashid [163]
3 years ago
9

Help me please Solve the system algebraically using substitution.

Mathematics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

y = 5/3

x = 8/3

Steps:

y = x - 1

2x + y = 7

Substitute y = x-1

(2x + x - 1 = 7)

Simplify: 3x - 1 = 7

Isolate x: 3x - 1 = 7:  x=8/3

Plug the valuse of x into the other equation (y = x- 1):    y = 8/3 - 1

8/3 - 1 = 5/3

y = 5/3

y = 5/3, x = 8/3

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Answer: Surface area is equal to 200cm^{2}

Volume is equal to 333.33cm^{3}

Step-by-step explanation:

First, let's do surface area.

The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base

The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.

The lateral height is given as 5 cm.

The area of the base is 10(10) = 100.

We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200cm^{2}.

Now for volume.

The volume of a pyramid is equal to 1/3(area of the base)(height).

We already have the area of the base, which is 100.

The height is given as 10 cm.

Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33cm^{3}.

Hope this helps!

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