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Rashid [163]
3 years ago
9

Help me please Solve the system algebraically using substitution.

Mathematics
1 answer:
cluponka [151]3 years ago
3 0

Answer:

y = 5/3

x = 8/3

Steps:

y = x - 1

2x + y = 7

Substitute y = x-1

(2x + x - 1 = 7)

Simplify: 3x - 1 = 7

Isolate x: 3x - 1 = 7:  x=8/3

Plug the valuse of x into the other equation (y = x- 1):    y = 8/3 - 1

8/3 - 1 = 5/3

y = 5/3

y = 5/3, x = 8/3

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