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VikaD [51]
3 years ago
5

Side a of a triangle is 4 cm longer than side b. Side c is twice as long as side b. What is the length of each side if the perim

eter is 28 cm?
Draw and label picture. Show all work with labeled answer.
Mathematics
1 answer:
vivado [14]3 years ago
3 0
a=b+4\\
c=2b\\
a+b+c=28\\\\
b+4+b+2b=28\\
4b=24\\
b=6\\\\
a=6+4\\
a=10\\\\
c=2\cdot6\\
c=12\\\\
\boxed{a=10,b=6,c=12}

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Step-by-step explanation:

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5 0
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Suppose that f(5) = 1, f '(5) = 4, g(5) = −9, and g'(5) = 5. Find the following values.
stiv31 [10]
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5 0
3 years ago
5(1 – 5n) = -4n+5<br> Helppppp
Crank

In this question, you're solving for n.

Solve for n:

5(1 - 5n) = -4n+5

<em>Use the distributive property</em>

5 - 25n = -4n + 5

<em>Add 25n to both sides</em>

5 = 21n + 5

<em>Subtract 5 from both sides</em>

0 = 21n

<em>Divide both sides by 21</em>

n = 0

Answer:

n = 0

8 0
3 years ago
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Solnce55 [7]

Answer:

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Step-by-step explanation:

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subtract the x1 and y1 which is -1--1 equal to 0

now same goes for x2/y2 we subtract them

which we end up getting 10

but because we have 0 whatever number we get it doesn't matter because at the end our answer will end up being 0.

7 0
3 years ago
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