1/2in = 16 mi 2 3/4 in without whole numbers [(denominator ×whole) + numerator] / denominator 4×2 = 8 +3 = 11/4 Find common denominator for 1/2 and 11/4 (common D Is 4) Multiply 1/2 by 2/2 2/4 in = 16 mi divide this by 2 2/4 ×1/2 = 1/4 16 /2 = 8 1/4 = 8 1/4 goes into 11/4 11 times Multiply 8 times 11 88 miles (D)
End zone to end zone is = length so his scale is 6 in and in real life it is 360 ft To find scale divide 360 by 6 1in = 60 ft (B)
160 ft wide (divide 160 by 60 ft ) fraction 160/60 is a fraction now simplify 16/6 Common factors of both numbers is 2 Simplify by 2 8/3 Make into whole number fraction 3 goes into 8 two times (2×3=6)(2 becomes whole number) while there's is 2 left over( 8 -6=2) (becoming the numerator) 2 2/3 in (B)
120 ft long 80 ft wide
24 in is scale of "long" Divide 120 by 24 120÷24=5 So 5in in scale equals 1ft in real life To find width in scale divide 80 by 5 80/5= 16in (A)
If you have any trouble understanding feel free to let me know I will try to explain as best as I can :)
