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4 years ago

12

PLS HELP ME ASAP FOR 1, 2, 3, and 4 (SHOW WORK!!) + LOTS OF POINTS!!

1 answer:

Lera25 [3.4K]4 years ago

5 0

1/2in = 16 mi
2 3/4 in without whole numbers [(denominator ×whole) + numerator] / denominator
4×2 = 8 +3 = 11/4
Find common denominator for 1/2 and 11/4 (common D Is 4)
Multiply 1/2 by 2/2
2/4 in = 16 mi divide this by 2
2/4 ×1/2 = 1/4
16 /2 = 8
1/4 = 8
1/4 goes into 11/4 11 times
Multiply 8 times 11
88 miles (D)

End zone to end zone is = length so his scale is 6 in and in real life it is 360 ft
To find scale divide 360 by 6
1in = 60 ft (B)

160 ft wide
(divide 160 by 60 ft ) fraction
160/60 is a fraction now simplify
16/6
Common factors of both numbers is 2
Simplify by 2
8/3
Make into whole number fraction
3 goes into 8 two times (2×3=6)(2 becomes whole number) while there's is 2 left over( 8 -6=2) (becoming the numerator)
2 2/3 in (B)

120 ft long
80 ft wide

24 in is scale of "long"
Divide 120 by 24
120÷24=5
So 5in in scale equals 1ft in real life
To find width in scale divide 80 by 5
80/5= 16in (A)

If you have any trouble understanding feel free to let me know I will try to explain as best as I can :)

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Please #3 is wrong i need help i only need the answer to it

Vaselesa [24]

3x² + 4

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31

hope it helps...!!!

7 0

2 years ago

Read 2 more answers

Use the figure to complete each statement<br> 1-6. pleaseee help will give brainliest

labwork [276]

Answer:

1. UW // TX

2. VX // UY

3. UW ≅ TY ≅ YX

4. YW = $\frac{1}{2}$ TV

5. TX = 2 UW

6. ∠TXV ≅∠WUY

Step-by-step explanation:

The line segment joining the midpoint of two sides of a triangle is parallel to the third side and equal to half its length

In Δ XVT

∵ U is the midpoint of VT

∵ W is the midpoint of VX

∵ XT is the 3rd side of the triangle

→ By using the rule above

∴ UW // TX ⇒ (1)

∴ UW = $\frac{1}{2}$ TX

→ Multiply both sides by 2

∴ 2 UW = TX

∴ TX = 2 UW ⇒ (5)

∵ Y is the midpoint of TX

∴ TY = YX = $\frac{1}{2}$ TX

∵ UW = $\frac{1}{2}$ TX

∴ UW ≅ TY ≅ YX ⇒ (3)

∵ U is the midpoint of VT

∵ Y is the midpoint of XT

∵ VX is the 3rd side of the triangle

→ By using the rule above

∴ UY // VX

∴ VX // UY ⇒ (2)

∴ UY = $\frac{1}{2}$ VX

∵ W is the midpoint of VX

∵ Y is the midpoint of XT

∵ TV is the 3rd side of the triangle

→ By using the rule above

∴ YW // TV

∴ YW = $\frac{1}{2}$ TV ⇒ (4)

∵ 2 Δs UYW and XVT

∵ UY = $\frac{1}{2}$ XV

∵ YW = $\frac{1}{2}$ VT

∵ WU = $\frac{1}{2}$ TX

∴ $\frac{UY}{XV}$ = $\frac{UW}{VT}$ = $\frac{WU}{TX}$ = $\frac{1}{2}$

→ By using the SSS postulate of similarity

∴ ∠TXV ≅∠WUY ⇒ (6)

4 0

3 years ago

Solve.<br> 7 pounds x 16 ounces =<br> pounds plz hero

Rama09 [41]

The answer is 7 pounds because 16 ounces is equal to 1 pound so 7 pounds times 1 pound would equal 7 pounds.

4 0

3 years ago

Part a: if angle a and angle b are vertical angles, what is the value of X?

Blizzard [7]

Answer:

a. x = 8

b. m<B = 140

Step-by-step explanation:

a.

m<A = m<B

40 = 5x

x = 8

b.

m<A + m<B = 180

m<B = 180 - m<A

m<B = 180 - 40

m<B = 140

7 0

3 years ago

The band has 30 more members than the school chorale. If each group had 10 more members, the ratio of their membership would be

vladimir1956 [14]

Answer:

80 members

Step-by-step explanation:

Let the band members be= b and the chorale members= c

Then, according to question, b=c+30 and $\frac{b+10}{c+10}=\frac{3}{2}$

⇒ $2(b+10)=3(c+10)$

⇒ $2b+20=3c+30$

⇒ $2b-3c=30-20$

⇒ $2b-3c=10$

Now, substituting the value of b=c+30, we get

⇒ $2(c+30)-3c=10$

⇒ $2c+60-3c=10$

⇒ $-c=-50$

⇒ $c=50$

Therefore, $b=c+30$

$b=50+30=80$

Therefore, there are 80 members in the band.

8 0

3 years ago