Answer:
- C = 0.97m
- $1164 for 1200 miles
- 845 miles for $820
Step-by-step explanation:
Given a car's cost of operation is $485 for 500 miles, you want an equation relating cost for m miles, and solutions to that equation for 1200 miles, and for a cost of $820.
<h3>Cost per mile</h3>
The cost per mile is found by dividing the cost by the associated number of miles:
$485/(500 mi) = $0.97 /mi
<h3>Equation</h3>
The equation for the cost will show the cost as the cost per mile multiplied by the number of miles:
C = 0.97m . . . . . where C is cost in dollars for m miles driven
<h3>1200 miles</h3>
The cost for driving $1200 miles will be ...
C = 0.97(1200) = $1164
The cost of driving 1200 miles is $1164.
<h3>$820</h3>
The number of miles that can be driven for a cost of $820 is ...
820 = 0.97m
m = 820/0.97 = 845.36
About 845 miles are driven for a cost of $820.
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
This is so blurry, can you take another picture or type the questions out please/
Answer:9.9
Step-by-step explanation:
Add up the scores and dividing the total by the number of scores.
