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Anestetic [448]
3 years ago
12

The net of a rectangular prism is shown.

Mathematics
1 answer:
Natali [406]3 years ago
6 0
It should be D. Because the equation is 2(width+ height + length

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Find the value of x.<br> B<br> 6<br> X+1<br> D<br> E<br> С<br> A<br> x = [?]
WITCHER [35]

Answer:

x = 2

Step-by-step explanation:

Given a line parallel to a side of a triangle and intersecting the other 2 sides then it divides those sides proportionally, that is

\frac{6}{x+1} = \frac{4}{x} ( cross- multiply )

6x = 4(x + 1)

6x = 4x + 4 ( subtract 4x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

8 0
2 years ago
Please answer correctly! I will mark you as Brainliest!
boyakko [2]
252.828911927301718279402738
3 0
2 years ago
Read 2 more answers
JUST ANSWER PLEASE!!! QUICK
jeka57 [31]

Answer:

<u>Options 1 and 3</u>

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

We will check which system of equation has the same solution.

<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

                 (P+2T)x + (Q+2U)y = R-2V  ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

 (P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

<u>System C)</u> (T-P)x + (U-Q)y = V-R  ⇒(5)

                  Tx + Uy = V  

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

<u>System D)</u> (T-P)x + (Q+U)y = V-R  ⇒(6)

                  Tx + Uy = V  

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) <u>OR </u>(T-P) and (Q-U)

So, system D has not the same solution of (2,9)

<u>System E)</u> (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

                  Tx + Uy = V  

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

<u>Options 1 and 3</u>

5 0
2 years ago
X^6 * x^-4<br><br> EXPONENTS QUIZ <br> ( YOU CANT GET A FRACTION OR A DESMIL!)
Varvara68 [4.7K]

Answer:

The answer is x².

Step-by-step explanation:

1) Use product rule: x^a x^b = x^a + b.

{x}^{6 - 4}

2) Simplify 6 - 4 to 2.

{x}^{2}

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u>²</u>

6 0
3 years ago
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sam and james win £500 in a competition. they share the money 3:7. sam gives 35% of the money he wins to his brother, harry. how
Black_prince [1.1K]
Sam gets (500/10)*3=150<span>£
harry gets (150/100)*35= 52.5</span>£
6 0
3 years ago
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