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const2013 [10]
3 years ago
8

Find the volume of a box that measures 4 cm by 16 cm by 20 cm.

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Volume is l * w * h

Length * width * height


to find the volume we would just plug in the values for the length width and the height.

4 * 16 * 20

64 *20 = 1280.

The volume of the box is 1280 cubic units.


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At a football game, the ratio of men to women is 4:1 There are 9,000 people in total, and each ticket costs £10 Calculate the am
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Answer:

£72000

Step-by-step explanation:

According to the Question,

  • Given, At a football game, the ratio of men to women is 4:1 & There are 9,000 people in total

Thus, 5 ⇒ 9000 People

So, 4 ⇒ 7200 People(Men)

      1 ⇒ 1800 People(Women)

  • And, each ticket costs £10

Thus, The amount of money made from tickets sold to men is 7200 total Men x £10 Per Ticket Cost ⇒ £72000.

4 0
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Which equation represents the solution of the equation 6x - 18 = 30?
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Answer:

x=8

Step-by-step explanation:

firstly take 30+18 which equals 48 and then divide that by six which will give you 8 as your answer

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In total Dan dranked 11/8 of his bottle or as a mixed number 1 and 3/8 of his bottle.

Step-by-step explanation:

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if i had 100 cookies and my friend has 50, but he took 50 more from me, and now i have 150 cookies and a dead body how many dead
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compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
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