Answer:
Step-by-step explanation:
we know that
The area of a regular hexagon is the same that the area of 6 equilateral triangles
The area of 6 equilateral triangles applying the law of sines is equal to
![A=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
where
b is the length side of the regular hexagon
we have
substitute
![A=6[\frac{1}{2}(10)^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%5E2sin%2860%5Eo%29%5D)
Answer:
x=3
Step-by-step explanation:
2(x+1)=x+5
Use the distributive property to multiply 2 by x+1.
2x+2=x+5
Subtract x from both sides.
2x+2−x=5
Combine 2x and −x to get x.
x+2=5
Subtract 2 from both sides.
x=5−2
Subtract 2 from 5 to get 3.
x=3
Isolate the variable by dividing each side by factors that don't contain the variable.
h = −8
<span>(2x + y2)<span>5 heres you answer your so welcome</span></span>
