All categories

3 years ago

I NEED HELP WITHIN AN HOUR!!! HELP!!

2 answers:

7 0

In order to find the coffee shop location, you find the midpoint of the church and the school.
Church: (100, 50) and School: (200, 100)
Midpoint or Coffee shop: (150, 75)
x=(100+200)/2=150
y=(50+100)/2=75

Hatshy [7]3 years ago

4 0

(150, 75)

Hope this helps you out Elizabeth0915! :D

You might be interested in

T. The entropy change As, for an ideal gas is given by the following formula: dT dV As=1C [c. R T V 7 where T is the thermodynam

MissTica

Answer:

The entropy change AS, for an ideal gas is given by: dt V Where T is the thermodynamic temperature, V is the volume and R=8.314. Determine the entropy change when a gas expands from 1 litre to 3 litres for a temperature rise from 100K to 400K given that: Cv = 45 + 6 x 10-T + 8 x 10-6T2 b) The average value of a complex voltage waveform is given by: V = ( 10 (10sin ox +3sin 30x +2 sin 508) dt Evaluate Vav correct to 2 decimal places.

7 0

2 years ago

Roopa takes 8

Molodets [167]

Answer:

Since them taken same time so the fraction is 1/1

5 0

2 years ago

Can you simplify (9c^8)^1/2

Tamiku [17]

Answer: 9c8

———

Step-by-step explanation:

32c8

Simplify 32c8———

7 0

2 years ago

Y=f(x) = (1/2)<br> Find f(x) when x = 1

sammy [17]

The value of function on x=1 is 0.5

Step-by-step explanation:

In order to find the value of a function on given input, the input is put at the place of variable in the function.

Given function is:

$f(x) = (\frac{1}{2})^x$

We have to find the value of function on x = 1

Putting x = 1 in function

$f(1) = (\frac{1}{2})^1\\= \frac{1}{2}\\= 0.5$

Hence,

The value of function on x=1 is 0.5

Keywords: Functions variables

Learn more about functions at:

LearnwithBrainly

7 0

3 years ago

What is the solution to log2(2x^3-8)-2log2(x)=log2(x)

Charra [1.4K]

$\bf \textit{Logarithm of rationals}
\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}
\\\\
log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\
-------------------------------$

$\bf log_2(2x^3-8)-2log_2(x)=log_2(x)
\\\\\\
log_2(2x^3-8)-log_2(x^2)=log_2(x)\implies log_2\left( \cfrac{2x^3-8}{x^2} \right)=log_2(x)
\\\\\\
\textit{since both sides are getting }log_2\textit{ we can simply undo that}
\\\\\\
\cfrac{2x^3-8}{x^2}=x\implies 2x^3-8=x^3\implies x^3-8=0
\\\\\\
x^3=8\implies x=\sqrt[3]{8}\implies x=2$

5 0

2 years ago

Read 2 more answers