H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
<h3>
Answer: 3 units</h3>
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Explanation:
The y coordinates are identical, so we just need to focus on the x coordinates.
Going from 0 to -3 is a distance of 3 units. Drawing out a number line might help.
Or we could apply subtraction and absolute value
|x1-x2| = |0-(-3)| = |0+3| = |3| = 3
which is the same as
|x2-x1| = |-3-0| = |-3| = 3
The absolute value is to ensure the result is never negative. Distance is never negative.
Side note: if the y coordinates weren't the same, then we'd have to use either the pythagorean theorem or the distance formula.
Answer:
The true statements are (D) and (E). This is a square with sides equal to 5 units so that means that its perimeter is 4×(5 units) or 20 units and its area is (5 units)×(5 units) or 25 units^2.
