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Tema [17]
3 years ago
11

If 9 oranges cost £1.62 how much is 1 orange

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0
.18
.90
but i don't recognize that currency  
hope this helps
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Add the integers.<br><br> 1. -2 +(-5)<br><br> 2. -2 +(-2)<br><br> 3. -13 +9
Maru [420]
-7 because when it’s +(-) it’s always the same as the outside sign
-4 same thing explained above
-4

hope this helps
7 0
2 years ago
I NEED PART B AND C DONE I DID PART A, PLEASE HELP AND TELL ME WHAT PART YOU ARE SOLVING ALSO LOTS OF POINTS!!!
RideAnS [48]

Answer:

(8,10) is not a solution

Step-by-step explanation:

Cuz it’s not on both inequality shaded part but just one of them and also when we substitute one is true and the other one is false

2x + y _< 8

2(8) + 10 _< 8

18 + 10 _< 8

28 _< 8 false

X + y _> 4

8 + 10 -> 4

18 _> 4 true

7 0
3 years ago
Read 2 more answers
Explain why 1 hundred 4 tens and 14 tens name the same amount.
artcher [175]
Because 14 tens is 10+4 tens
10 tens is a hundred
so 14 tens is a hundred + 4 tens
7 0
3 years ago
B. What number is equal to 280 tenths + 19 thousandths?<br><br> HELP!!
Kaylis [27]

The number that equals 280 tenths + 19 thousandths is 28.019

<h3>How to determine the number?</h3>

The statement is given as:

280 tenths + 19 thousandths

Rewrite the terms of the expression as fractions

So, we have

280/10 + 19/1000

Evaluate the quotients

28.0 + 0.019

Add both numbers

28.019

Hence, the number that equals 280 tenths + 19 thousandths is 28.019

Read more about expressions at:

brainly.com/question/723406

#SPJ1

3 0
1 year ago
What are the solutions to the equation 2(x-3)^2=54 ?
erastova [34]

Answer:

      x =(6-√108)/2=3-3√ 3 = -2.196

 x =(6+√108)/2=3+3√ 3 = 8.196

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

2 • (x - 3)2 - 54 = 0

Step  2  :

 2.1    Evaluate :  (x-3)2   =  x2-6x+9 

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   2x2 - 12x - 36  =   2 • (x2 - 6x - 18) 

Adding  9  has completed the left hand side into a perfect square :

   x2-6x+9  =

   (x-3) • (x-3)  =

  (x-3)2  (x-3)1 =

   x-3

Now, applying the Square Root Principle to  Eq. #4.3.1  we get:

   x-3 = √ 27

Add  3  to both sides to obtain:

   x = 3 + √ 27

Since a square root has two values, one positive and the other negative

   x2 - 6x - 18 = 0

   has two solutions:

  x = 3 + √ 27

   or

  x = 3 - √ 27

Solve Quadratic Equation using the Quadratic Formula

 4.4     Solving    x2-6x-18 = 0 by the Quadratic Formula .

 According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

            - B  ±  √ B2-4AC

  x =   ————————

                      2A

  In our case,  A   =     1

                      B   =    -6

                      C   =  -18

Accordingly,  B2  -  4AC   =

                     36 - (-72) =

                     108

Applying the quadratic formula :

               6 ± √ 108

   x  =    —————

                    2

Can  √ 108 be simplified ?

Yes!   The prime factorization of  108   is

   2•2•3•3•3 

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 108   =  √ 2•2•3•3•3   =2•3•√ 3   =

                ±  6 • √ 3

  √ 3   , rounded to 4 decimal digits, is   1.7321

 So now we are looking at:

           x  =  ( 6 ± 6 •  1.732 ) / 2

Two real solutions:

 x =(6+√108)/2=3+3√ 3 = 8.196

or:

 x =(6-√108)/2=3-3√ 3 = -2.196

7 0
3 years ago
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