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Tema [17]
3 years ago
11

If 9 oranges cost £1.62 how much is 1 orange

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0
.18
.90
but i don't recognize that currency  
hope this helps
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Rewrite the following in the form log(c).<br> log(10) - log(2)
serg [7]

Answer:

log 5

Step-by-step explanation:

We can rewrite this by using a property of logs

log a - log b = log (a/b)

log(10) - log(2)

log(10/2)

log 5

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3 years ago
What is the best estimate for the length of a bulletin board in meters
Reptile [31]
Bulletin boards can be in all shapes and sizes. There is no correct or incorrect answer to this problem. 
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3 years ago
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A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
Solve for W. MUST SHOW WORK!!<br> -3W +27 = 6
Travka [436]

Answer:

W=7

Step-by-step explanation:

-3W+27=6

Subtract 27 from both sides to isolate the variable.

-3W=-21

Divide by -3 to solve for W

w=7

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3 years ago
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What is the Greatest Common Factor of 96x2 and 88x?
hodyreva [135]

Factor the GCF from 96x2 + 88x. Use the drop-down menus to complete the statements. The GCF of 96x2 and 88x is . Each term written as a product, where one factor is the GCF, is . The factored form of the expression is

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