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butalik [34]
2 years ago
5

All the dimensions of a pentagon were multiplied by the same factor, and the area of the figure changed by a factor of 25. By wh

at factor were the dimensions of the pentagon multiplied?
12. 5

625

5

50
Mathematics
1 answer:
elena-s [515]2 years ago
8 0

5


reason is because if you’re pentagon has lines of 5 then the area would be 25
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dezoksy [38]
2.43 x 10^2

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3 years ago
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Find X and Y and show please show calculations
torisob [31]

Answer:

Y = 90

X = 52

Step-by-step explanation:

Y is on a straight line. The sum of the angles on a straight line is 180.

The only other angle (that is marked) on this straight line, is a 90 degree one. So, <y + 90 = 180.

<y = 90.

Now <x + 38 = 90

so, x = 52

6 0
3 years ago
How to solve for x where (2^x)*x =n?
Molodets [167]
Tough call.  
You may have to use Newton's Method or something like that.
Graph y=2^x and then graph n/x on the same set of axes.  You may have to assign some arbitrary value to n to make this work.  From the graph you can read off the approximate coordinates of the point of intersection.
4 0
3 years ago
Help!! 50 points and brainliest!
Viktor [21]

Answer:

Second choice:

x=2t

y=4t^2+4t-3

Fifth choice:

x=t+1

y=t^2+4t

Step-by-step explanation:

Let's look at choice 1.

x=t+1

y=t^2+2t

I'm going to subtract 1 on both sides for the first equation giving me x-1=t. I will replace the t in the second equation with this substitution from equation 1.

y=(x-1)^2+2(x-1)

Expand using the distributive property and the identity (u+v)^2=u^2+2uv+v^2:

y=(x^2-2x+1)+(2x-2)

y=x^2+(-2x+2x)+(1-2)

y=x^2+0+-1

y=x^2

So this not the desired result.

Let's look at choice 2.

x=2t

y=4t^2+4t-3

Solve the first equation for t by dividing both sides by 2:

t=\frac{x}{2}.

Let's plug this into equation 2:

y=4(\frac{x}{2})^2+4(\frac{x}{2})-3

y=4(\frac{x^2}{4})+2x-3

y=x^2+2x-3

This is the desired result.

Choice 3:

x=t-3

y=t^2+2t

Solve the first equation for t by adding 3 on both sides:

x+3=t.

Plug into second equation:

y=(x+3)^2+2(x+3)

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

y=(x^2+6x+9)+(2x+6)

y=(x^2)+(6x+2x)+(9+6)

y=x^2+8x+15

Not the desired result.

Choice 4:

x=t^2

y=2t-3

I'm going to solve the bottom equation for t since I don't want to deal with square roots.

Add 3 on both sides:

y+3=2t

Divide both sides by 2:

\frac{y+3}{2}=t

Plug into equation 1:

x=(\frac{y+3}{2})^2

This is not the desired result because the y variable will be squared now instead of the x variable.

Choice 5:

x=t+1

y=t^2+4t

Solve the first equation for t by subtracting 1 on both sides:

x-1=t.

Plug into equation 2:

y=(x-1)^2+4(x-1)

Distribute and use the binomial square identity used earlier:

y=(x^2-2x+1)+(4x-4)

y=(x^2)+(-2x+4x)+(1-4)

y=x^2+2x+-3

y=x^2+2x-3.

This is the desired result.

3 0
3 years ago
Read 2 more answers
Given: &lt;PQR is a right angle Prove: &lt;PQS and &lt;SQR are complemantary​
amm1812

Answer:

see the explanation

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

m∠PQS+m∠SQR=m∠PQR ----> equation A (by Addition Angle Postulate)

we have that

m∠PQR=90° ----> equation B given problem (because is a right angle)

substitute equation B in equation A

m∠PQS+m∠SQR=90°

Remember that

Two angles re complementary is their sum is equal to 90 degrees (Definition of complementary angles)

therefore

m∠PQS and m∠SQR are complementary angles

3 0
3 years ago
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