new copy machine can produce five more than twice the number of copies per hour of the old copy machine. If the new machine prod
1 answer:
The old machine can print 100 copies per hour.
Step-by-step explanation:
Given,
Copies printed per hour by new machine = 205 copies
Let,
x represent the number of copies by old machine.
According to given statement;
Copies printed by new machine = five more than twice the number of copies per hour of the old copy machine.
Dividing both sides by 2
The old machine can print 100 copies per hour.
Keywords: addition, division
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Answer:
A. The y-intercept of g(x) is less than the y-intercept of f(x).
Step-by-step explanation:
The x-intercept, or when x = 0, of f(x) is -4, the x-intercept of g(x) is -8, so g(x) are neither greater nor equal to f(x), this marks out C and D. The y-intercept, or when y = 0, is in this case f(x) or g(x). The y-intercept of f(x) is 16, the y-intercept of g(x) is 4, so the y-intercept of g(x) is not equal to the y-intercept of f(x), this marks out B. Now to check A, 4 < 16, so y-intercept of g(x) < y-intercept of f(x), the answer is A
Answer:
The expressions which equivalent to are:
⇒ B
⇒ C
Step-by-step explanation:
Let us revise some rules of exponent
×
=
Now let us find the equivalent expressions of
A.
∵ 4 = 2 × 2
∴ 4 =
∴ =
- By using the second rule above multiply 2 and (n + 2)
∵ 2(n + 2) = 2n + 4
∴ =
B.
∵ 4 = 2 × 2
∴ 4 = 2²
∴ = 2² ×
- By using the first rule rule add the exponents of 2
∵ 2 + n + 1 = n + 3
∴ =
C.
∵ 8 = 2 × 2 × 2
∴ 8 = 2³
∴ = 2³ ×
- By using the first rule rule add the exponents of 2
∵ 3 + n = n + 3
∴ =
D.
∵ 16 = 2 × 2 × 2 × 2
∴ 16 =
∴ =
×
- By using the first rule rule add the exponents of 2
∵ 4 + n = n + 4
∴ =
E.
is in its simplest form
The expressions which equivalent to are:
⇒ B
⇒ C