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Butoxors [25]
3 years ago
8

Fill in the blank The equation y=*blank* models the relationship

Mathematics
1 answer:
NISA [10]3 years ago
5 0

Answer:

y=14x

Step-by-step explanation:

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What is the answer? 5x+3x+2y+4y=
Lubov Fominskaja [6]

Answer:

8x+6y

Step-by-step explanation:

add the coefficients of like terms with the same variable

4 0
3 years ago
1. Simplify: <br> a. -2(4ab3)2 b. 6a-5 * 2a4 <br><br> SHOW ALL WORK PLEASE THANK YOU!
marusya05 [52]
A.  -2(4ab^{3} )^{2}
-2(16a^{2}b^{6})
-32a^{2}b^{6}

b.  6a^{-5} * 2a^{4}
(6*2)a^{-5+4}
12a^{-1}
6 0
4 years ago
Read 2 more answers
Find the equation of a line parallel to y'= -8x+6.
Verizon [17]

Answer:

The equation must include -8 as the slope

Step-by-step explanation:

Hi there!

Two key points to keep in mind:

  1. Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0).
  2. Parallel lines always have equal slopes

Given the equation y=-8x+6, we can identify that -8 is in the place of m in y=mx+b, making it the slope.

For a line to be parallel to y=-8x+6, it would have to have a slope of -8 as well. This is the only quality a line needs to be parallel to this given line.

I hope this helps!

4 0
3 years ago
How do you tell if a number is divisible by 8
eimsori [14]
If the number is a multiple of 8, it is divisible by 8.
The multiples of 8 are: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88... etc.

If a number is very big, let's say 176, see if you can deduct 80 from it. For this, 176 can be deducted by 80 twice, which will give you a remainder of 16 (I.e. 176 - 80 - 80 = 16". If this remainder (i.e. 16) is divisible by 8, 176 is divisible by 8.

For even larger numbers, try deducting 800, or even 8000.

Let's say you're trying to see if 2464 is divisible by 8. In this case, 2464 can be deducted by 800 thrice (I.e. 2464 - 800 - 800 - 800 = 64), and 64 is its remainder. Since 64 is divisible by 8, 2464 is divisible by 8.

Hope this helps! :)
5 0
4 years ago
Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random
Maurinko [17]

Answer:

D)

(0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the random sample size 'n' = 50

The sample proportion

                       p^{-} = \frac{32}{50} = 0.64

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(p^{-} - Z_{0.90} \sqrt{\frac{p(1-p)}{n},  } , p^{-} +Z_{0.90} \sqrt{\frac{p(1-p)}{n} })

<u><em>Step(ii):-</em></u>

Level of significance = 0.90

Z₀.₉₀ = 1.645

(0.64 - 1.645 \sqrt{\frac{0.64(1-0.64)}{50},  } , 0.64 +1.645 \sqrt{\frac{0.64(1-0.64)}{50} })

(0.64 - 1.645 \sqrt{\frac{0.64(0.36)}{50},  } , 0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })

(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)

(0.52846 , 0.75166)

<u><em>Final answer:-</em></u>

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

5 0
3 years ago
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