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madreJ [45]
3 years ago
14

thurman put $90 into an account that pays 4.4% interest compounded quarterly. according to the rule of 72 approximately how long

will it take for his money to double
Mathematics
2 answers:
ollegr [7]3 years ago
7 0

Answer:

16.4 is the answer on APEX

Dominik [7]3 years ago
3 0
16.4 - Apex Answer & general answer 

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Answer ASAP pls pls
LiRa [457]
D be the correct answer
6 0
3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
Please help please need help ASAP
Anuta_ua [19.1K]

The altitude of a triangle is a line segment through a vertex and perpendicular to a line containing the side opposite the vertex.

Answer: \overline{A F}

6 0
3 years ago
HELP !!!! picture is shown GEOMETRY
kenny6666 [7]
The right triangle is also Isosceles. It has two equal angles of 45°.

(hypotenuse)² = 2S²

4 = 2S² => S = √2

Therefore B is the correct answer.
8 0
3 years ago
A box contains 17 balls numbered 1 through 17. Two balls are drawn in succession without replacement. If the second ball has the
Brilliant_brown [7]

Answer:

1 ; 7 /17

Step-by-step explanation:

17 balls numbered 1 through 17

Picking without replacement :

If the second ball picked = 4

P(first ball has a smaller number)

Numbers less Than = (3, 2, 1)

P(number less than second ball Given 4 is drawn for second ball) :

= (3/17 * 1/16) ÷ (3/17 * 1/16) +) 14/17 * 0)

= (3 / 272) / (3 /272) * 0

= 3 / 272 * 272 / 3

= 1

2.)

(8/17 * 7/8) ÷ (8/17 * 7/8) + (9/17 * 1/17)

7/17 ÷ (7 /17) + 10/17

7 /17 ÷ 17/17

7/17 ÷ 1

7 /17

7 0
3 years ago
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