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deff fn [24]
3 years ago
14

Can some one help me plss

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
6 0

Irrational

Irrational

Rational

Rational

Irrational

Rational

Irrational

Irrational

Sorry if anything is wrong, I went off of memory! :)

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Evaluate each expression for g=10 9-4g+1=?
Viktor [21]
-30, 10*4=40 so you do 9-40+1 which is equal to -30
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My favorite songstress gives away 25% of the cells of her signature fragrance collection to her charity. last month her cells we
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Answer:

$300

Step-by-step explanation:

Multiply 1,200 by .25 and that is your answer

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3 years ago
Leo made a container to store his camping gear. The container is in the shape of a rectangular prism. The container has material
Contact [7]
<span>(a) What is the capacity of the container?
Volume = length * width * height
V = 4ft * 2ft * 3ft
V = 24 ft</span>³
<span>
(b) How much material was used to make the container?
Surface area = sum of 6 faces of the prism
4 ft x 3 ft = 12 ft</span>² → 12 ft² x 2 = 24 ft²
<span>4 ft x 2 ft = 8 ft</span>² → 8 ft² x 2 = 16 ft²
<span>2 ft x 3 ft = 6 ft</span>² → 6 ft² x 2 = 12 ft²
<span>
Surface area = 24 ft</span>² + 16 ft² + 12 ft² = 52 ft²<span>

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3 years ago
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​ Find the output, h, when the input, x, is - 18.<br><br> ​ h=17+ x/6
Nookie1986 [14]

Answer:

h = 20

Step-by-step explanation:

h = 17 + x/6

h = 17 + (18) / 6

h = 17 + 3

h = 20

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3 years ago
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Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a
Brums [2.3K]

Answer:

The minimum sample size is  n  =135

Step-by-step explanation:

From the question we are told that

   The confidence interval is ( lower \ limit  = \  0.44,\ \ \   upper \ limit  = \ 0.51)

    The margin of error is  E =  0.1

   

Generally the sample  proportion can be mathematically evaluated as

     \r p = \frac{ upper \ limit  + lower \ limit }{2}

    \r p = \frac{ 0.51 + 0.44}{2}

    \r p = 0.475

Given that the confidence level is  98% then the level of significance can be mathematically evaluated as

         \alpha = 100 -  98

        \alpha = 2\%

        \alpha =0.02

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table  

   The value is

        Z_{\frac{\alpha }{2} } =  2.33

Generally the minimum sample size is evaluated as

      n  =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 *  \r p (1- \r p )

     n  =[ \frac { 2.33}{0.1} ]^2 *  0.475(1- 0.475 )

     n  =135

6 0
3 years ago
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