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3 years ago

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Of all the people that attend movies, 67% are in the 12-29 age group. At one theater, 300 people attended a showing of a certain

movie. How many were in the 12-29 age group?

2 answers:

andreyandreev [35.5K]3 years ago

6 0

300*2/3=200 people who would be expected to be in the 12-29 age group.

aleksklad [387]3 years ago

5 0

Ratio and proportion x/300=67/100 cross multiply 100x= 20100 x= 201 students hope this helps

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Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0

Westkost [7]

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

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2 years ago

23/50 of Zanders friends prefer to stay home on Friday night what percent of Xander's friends prefer to stay home on Friday nigh

koban [17]

Answer:

46% of Xander's friends prefer to stay home on Friday nights.

Step-by-step explanation:

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ value}$

As given

$\frac{23}{50}\ of\ Zanders\ friends\ prefer\ to\ stay\ home\ on\ Friday\ night.$

i.e

Zanders friends prefer to stay home on Friday night = 23

Total numbers of Zanders friends are 50.

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Total value = 50

Put in the formula

$Percentage = \frac{23\times 100}{50}$

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Therefore 46% of Xander's friends prefer to stay home on Friday nights.

3 0

3 years ago

Use the function F(3)<br> F(x) =(1/5)^x<br> A.)1/15<br> B.)1/125<br> C.)3/5<br> D.)3/125

nalin [4]

Here is your answer

B) 1/125

REASON:

Given,

$F (x)={(1/5)}^{x}$

for F (3)

Putting x=3, in above function we get

$F (3)= {(1/5)}^{3}= 1/125$

HOPE IT IS USEFUL

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3 years ago

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drek231 [11]

I believe the ratio in simplest form is 1.3 to 0.7.

<em>(Please mark this answer as Brainliest and leave a Thanks if I helped you!)</em>

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3 years ago

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Varvara68 [4.7K]

Answer:

$0.80

Step-by-step explanation:

-3 (1x + 1y = 3.2)

3x + 1y = 8

----------------

-3x - 3y = -9.6

+

3x + 1 y = 8

-------------------

0x -2y = -1.6

÷ -2

-----------------

y = 0.8

one hamburger costs $0.80

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3 years ago

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