Oh, this is easy. For any prism, you find the surface area by finding the are of all the sides. I will post all surface area formulas here, for reference
Cube:
Surface area = 6 × a2
Right circular cylinder:
Surface area = 2 × pi × r2 + 2 × pi × r × h
pi = 3.14
h is the height
r is the radius
Rectangular prism:
Surface area = 2 × l × w + 2 × l × h + 2 × w × h
l is the length
w is the width
h is the height
Sphere:
Surface area = 4 × pi × r2
pi = 3.14
r is the radius
Right circular cone:
Surface area = pi × r2 + pi × r ×( √(h2 + r2))
pi = 3.14
r is the radius
h is the height
l is the slant height
Right square pyramid:
Surface area = s2 + 2 × s × l
s is the length of the base
h is the height
l is the slant height
A quadrilateral with only 2 right angles could be a trapezoid so Balavan is wrong. Denna is right because if 3 angles are right angles the the fourth angle must also be a right angle and has to be a square or rectangle.
Are there answer choices for this one because I got something kind of weird
A = 3,953 in²
You find the area of the whole triangle:
1/2bh = 1/2(63+31)(63+62) = 5875
Then subtract the missing rectangle:
lw = (62)(31) = 1922
5875 - 1922 = 3953 inches
Since you're multiplying inches by inches, it's inches².
It’s function one cause if you find the slope on the table it’s 3/1 which is basically just 3. Then the y-intercept is -3.
Function 1 slope is 5 or 5/1 and y-intercept is 4
