440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze
<em><u>Solution:</u></em>
Let "x" be the gallons of 80 % antifreeze added
Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze
Final mixture is x + 80
Therefore, we can frame a equation as:
"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze
Thus, we get,
x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

Thus 440 gallons of 80 % antifreeze solution must be mixed
Since the two measures are vertical angles, you want to set them equal to each other :
6x+7=8x-17
-6x -6x
——————
7=2x-17
+17 +17
———————
24= 2x
X= 12
———
The answer is 12.
Answer:
4Hz
Step-by-step explanation:
Standard form of a sine or cosine function,
y = acos(b(x+c))
where a is the amplitude, b is the value to find the period. and c is the phase shift.
Period = \frac{2\pi}{b}
From the equation given in the question,

We can see:
Amplitude = 3,
Period = \frac{2\pi}{8\pi} = 1 / 4
Phase Shift = 1 / 16
Now we want to find the frequency.
Frequency = 1 / Period
= 1 / (1/4)
= 4Hz
Answer:
103.96
Step-by-step explanation:
The answer is 939.44 - 835. 48
we can do like: 939.44 - 835. 48 = 103.96 ( 938 -835 = 103 and 144 - 48 = 96).
Have a good day