The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
x=13
Step-by-step explanation:
ok so let x+y=22
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x and y are the 2 unkown Number
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x-y=4
their difference is 4
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add both equations
(x+y=22)
+(x-y=4)
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y's cancel out
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2x=26
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x=13
Answer:
5
Step-by-step explanation:
this will endure the bitextular number course and follow the index pattern once you do that follow the question to get 5
Answer:
48 - 8c
Step-by-step explanation:
let c be the number of coworkers
48 - 8c would be the expression because it starts with 48 and for every coworker 8 is subtracted.
