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pishuonlain [190]
3 years ago
8

Find the area of triangle DEF with vertices D(-1,2), E(3,-2) and F(-2,-2).*

Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

<em>The area of the triangle DEF is 10.</em>

Step-by-step explanation:

<u>Area of a Triangle:</u>

A triangle of base B and height H (both must be perpendicular) has an area of:

\displaystyle A=\frac{BH}{2}

The image below shows the triangle formed by the points DEF. It's important to notice the points E and F lie on the same horizontal line because they both have the same y-coordinate.

This fact simplifies the calculations since we can easily compute the length the of base as the difference of their x-coordinates:

B=3-(-2)=3+2=5

Being the base of a horizontal line, the height of the triangle can be calculated as the difference of y-coordinates of D and the height of that line.

H=2-(-2)=4

With these two values, we calculate the area:

\displaystyle A=\frac{5*4}{2}=10

The area of the triangle DEF is 10.

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3 years ago
What is the equation of the line that is parallel to this line and has a y-intercept of 1?
julsineya [31]

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2

Step-by-step explanation:


7 0
3 years ago
Read 2 more answers
Hello I need help on it ​
Gnoma [55]
It would be 78/4=19.5 which would mean that he would be able to set 19 tables. To be able to set all of the tables he would need 2 more napkins because 19*4=76. 78-76=2 so they would need 2 more to finish the last table.
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3 years ago
10. Expand and Simplify (r+3) (r+11)=
mihalych1998 [28]

Answer:

r^2 + 14r + 33

Step-by-step explanation:

Apply the "FOIL" method for multiplying two binomials:

(r+3) (r+11) = r^2 (first terms) +

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Combining ilke terms, we get:

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6 0
2 years ago
Help plz show work please
borishaifa [10]

Alright, so here we have a cone and a cylinder. The cone has a height of 12. The cylinder has a height of 10.5. Both shapes, because they're on top of each other, have a diameter of 26 or a <em>radius</em> of 13.

Equation for a cylinder: V_{cylinder} = \pi r^{2} h

Equation for a cone: V_{cone} = \frac{1}{3} \pi r^{2} h

We're going to add both of the volumes of these shapes as soon as we find them.

Cylinder:

V_{cylinder} = \pi r^{2} h\\= \pi (13)^{2} (10.5)\\\approx 5574.756

Cone:

V_{cone} = \frac{1}{3} \pi r^{2} h\\= \frac{1}{3} \pi (13)^{2} (12)\\\approx 2123.717

Add both values: 2123.717 + 5574.756 = 7698.473 cm³.

Hope this was helpful, let me know if I missed anything!

5 0
3 years ago
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