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crimeas [40]
3 years ago
12

(20 points) Solve this algebra problem and show work. If it is correct you will be awarded the points and Brainliest answer. If

you are wrong your answer will be deleted and the points withdrawn from your account. Good luck.

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0
X+2y≤6  with x≥0 and y≥0 
2x+y≤6

1st) Find the 1st  shaded region: 1st Quadrant since x≥0 and y≥0

2nd) Let's find the x and y intercepts of 2x+y = 6
x-intercepts for y = 0 , x=6 →A(3,0)
y-intercepts for x = 0 , y =3→B(0,6) . Now Join AB
2nd shaded region

3rd) Let's find the x and y intercepts of x+2y = 6
x-intercepts for y = 0 , x=6 →C(6,0)
y-intercepts for x = 0 , y =3→D(0,3) . Now Join CD
3rd shaded region

4th) Now let's calculate the coordinate of the intersection point of
x+2y=6 and
2x+y =6  Solving it will give you x = 2 and y = 2 (coordinates of the intersection of AB with DC, le be E. (4th shaded region).

Re write all pairs:

A(3,6), B(0,6), C(6,0), D(0,3), E(2,2). Now plug in each pairs with the equation:

F= 5x + 2y

For A(3,6), →→F=15+12 = 25
For B(0,6), →→F=0+12 = 12
For C(6,0), →→F=30+0 = 30
For D(0,3), →→F=0+6 = 6
For E(2,2), →→F=20+4 = 14
So the max value of F= 5x+2y is 30 at C(6,0)
Hope that I didn't make any mistake

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2.5(4k+2)=12k solve for k
finlep [7]

Answer:

k = 2.5

Step-by-step explanation:

2.5 (4k+2) = 12k

10k + 5 = 12k

-10k

5 = 2k

5/2

2.5

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What is the slope-intercept form of the function described by this table?
Firdavs [7]

Answer:

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Step-by-step explanation:

I did this math problem a long time ago, I don't remember how I got the answer, I just have the answer lol

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3 years ago
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A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.
zmey [24]

Answer:

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation  

\bar X=2.2 represent the sample mean

s=0.29 represent the sample standard deviation

n=40 sample size  

\mu_o =2.1 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.1  

Alternative hypothesis:\mu > 2.1  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

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Answer:

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Step-by-step explanation:

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anzhelika [568]

Answer:

Lucey reads 10 pages fewer than Carey.

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