Given :
A complex number z = 10 - 13i .
To Find :
Which quadrant will the complex number (10 - 13i) be found.
Solution :
Coefficient of real part of complex number, r = 10.
Coefficient of imaginary part of complex number, i = -13.
Since, the coefficient of imaginary part is -ve and real part is +ve .
Therefore, the complex number is in 4th quadrant.
Hence, this is the required solution.
Answer:
From J to K: right 6 units, down 4 units
From K to J: left 6 units, up 4 units
First we have to see the formula of profit, which is
And it is given that profit should be atleast $150, that is
Let Ritax dollars per cake, so for 15 cakes, she charge 15x .
And she epent 30 dollars for 15 cakes.
So we will get
Adding 30 to both sides
Correct option is the second option .
Here,
y=mx+c
the slope of the line 6x+4y= -16 is -20.
if the two lines are perpendicular, the slope of 1st line * slope of second line=-1
the slope of the 2nd line is -1/2
y-y1=m(x-x1)
y-13=-1/2(x- -18)
when you solve, you get the equation of the line as 2y+x=50
In basic geometry, if two geometry objects intersect at right angles (90 degrees or π / 2 radians), they are vertical.
If two lines intersect at right angles, the line is perpendicular to another line. Explicitly (1) if two lines intersect, the first line is perpendicular to the second line. (2) At the intersection, the straight line angle on one side of the first line is cut by the second line into two congruent angles. Verticality can be shown as symmetric. That is, if the first line is perpendicular to the second line, then the second line is also perpendicular to the first line. Therefore, two straight lines can be said to be perpendicular (to each other) without specifying the order.
Learn more about Perpendicular here: brainly.com/question/7098341
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Answers:
<h3>1. -5</h3><h3>2. 7</h3><h3>3. 1</h3><h3>4. 5</h3>
Step-by-step explanation:
Plug in the x into the equation and solve.
<h3>Value 1: X = 5</h3>
Y = -2(5) + 5
Y = -10 + 5
Y = -5
<h3>Value 2: X = -1</h3>
Y = -2(-1) + 5
Y = 2 + 5
Y = 7
<h3>Value 3: X = 2</h3>
Y = -2(2) + 5
Y = -4 + 5
Y = 1
<h3>Value 4: X = 0</h3>
Y = -2(0) + 5
Y = 0 + 5
Y = 5
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