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OleMash [197]
3 years ago
9

Convert 1.51 to a fraction

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0
It would be 151/100 it ant be symplified anymore so
maria [59]3 years ago
3 0
Since one is a whole number that would stay the same then move onto the 51 part and since it's in the hundreds place it is out of 100 so you out the numerator 51 about 100 like this 51/100. Since you can't refuse it your final answer is 1 51/100
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A plant that is 6 inches tall grows 1 inch each week. Another plant is 4 inches tall and grows 2 inches each week
Darya [45]
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4 0
2 years ago
I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am
harina [27]

<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,  

-13 < x < 0     ------(1)

Also when number is subtracted from -11, result is positive.  

=>  -11 – x > 0

=> -11 > x   -------(2)  

So form 1 and 2  

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13.  There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

4 0
3 years ago
Find the 13th term of the arithmetic sequence -3x+7, -5x+3, -7x-1, ...
oksano4ka [1.4K]

Answer:

a₁₃ = - 27x - 41

Step-by-step explanation:

The nth term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3x + 7

d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)

                 = - 5x + 3 + 3x - 7

                 = - 2x - 4

Then

a₁₃ = - 3x + 7 + 12(- 2x - 4)

     = - 3x + 7 - 24x - 48

     = - 27x - 41

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3 years ago
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ra1l [238]

Just took the test and got the the correct answer *\(♡°▽°♡)/*

Look at the image down below!!


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3 years ago
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77julia77 [94]
A line would be best used to model the surface of an aquarium, by putting a line on top of the surface and checking if the water is level or not.
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