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Flauer [41]
3 years ago
15

Write an equivalent expression for the following by combining like terms: 4y − y + 7y

Mathematics
1 answer:
Assoli18 [71]3 years ago
4 0
4y - y + 7y

4y - y = 3y

3y + 7y = 10y

10y is your answer

hope this helps
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Ilia_Sergeevich [38]

Answer:

1/2 is the pre image for this

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Is either x=5 or x=3 a solution to 11- x <7
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Answer:

<h2><em><u>x = 5</u></em></h2>

Explanation:

11 - x < 7

  • 11 minus a number is less than 7

<em>Insert 5 into the equation</em>

11 - 5 < 7

<em>Simplify</em>

6 < 7

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<em>Insert 3 into the equation</em>

11 - 3 < 7

<em>Simplify</em>

8 < 7

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<h3><u><em>x = 5 is a solution to the equation 11 - x </em></u><u>< 7</u></h3><h3><u /></h3>

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3 years ago
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The product of twice a number and six is the same as the difference of eleven times the number and 6/5 . Find the number
Rom4ik [11]

Answer:

-6/5

Step-by-step explanation:

solution;

let,the number be x,

product of <u>twice</u><u> </u><u>of</u><u> </u><u>x</u> and <u>six</u> = the <u>difference </u>

<u>difference of eleven times x and 6/5</u>

or, (2x×6)=(11×x)-(6/5)

or, 12x = 11x - 6/5

or, 12x - 11x = -6/5

therefore,x =-6/5

Therefore, the number required is (-6/5) whose product of twice a number and six is the same as the difference of eleven times the number and 6/5 .

3 0
3 years ago
What is the median of the scores shown in the stem-and-leaf plot?
AlekseyPX
The answer is 88. Median is middle number and you don’t count the same number twice
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3 years ago
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A line includes the points (-39,49) and (0,0). What is its equation in slope-intercept form?
malfutka [58]

Answer:

The equation in the slope-intercept form will be:

y=-\frac{49}{39}x+0

Step-by-step explanation:

Given the points

  • (-39,49)
  • (0,0)

Finding the slope between the points using the formula

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-39,\:49\right),\:\left(x_2,\:y_2\right)=\left(0,\:0\right)

m=\frac{0-49}{0-\left(-39\right)}

m=-\frac{49}{39}

We know that the point-slope of the line equation is

y-y_1=m\left(x-x_1\right)

substituting m=-\frac{49}{39} and (-39,49)  in the equation

y-y_1=m\left(x-x_1\right)

y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)

Now writing the equation in slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept

y-49=\frac{-49}{39}\left(x-\left(-39\right)\right)

y-49=\frac{-49}{39}\left(x+39\right)

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

y-49=-\frac{49}{39}\left(x+39\right)

\mathrm{Add\:}49\mathrm{\:to\:both\:sides}

y-49+49=-\frac{49}{39}\left(x+39\right)+49

y=-\frac{49}{39}x+0              ∵ y=mx+b

Where

m=-\frac{49}{39} and the y-intercept i.e. b=0

Therefore, the equation in the slope-intercept form will be:

y=-\frac{49}{39}x+0

5 0
3 years ago
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