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zlopas [31]
3 years ago
14

Why don't we see the ground coming toward us?

Chemistry
1 answer:
Alexandra [31]3 years ago
5 0
Because we are moving faster than the ground
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How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Black_prince [1.1K]
The combustion of ethane is expressed in the balanced reaction C2H6 + 3.5O2= 2CO2 + 3 H2O. Given the mass of oxygen gas, we get the moles of ethane needed by converting this mass to mole (dividing my 32 g/mol), then multiply by 1/3.5 (stioch ratio) and the molar mass of ethane (30 g/mol). The answer is 16.69 grams ethane. 
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3 years ago
How do the orbits of a comet and earth compare?
TiliK225 [7]
Comets are balls of ice and dust in orbit around the Sun. The orbits of comets are different from those of planets - they are elliptical. A comet's orbit takes it very close to the Sun and then far away again.
8 0
4 years ago
The green areas on the diagram show the world's rainforests. What can you conclude about the location of rainforests?
Ber [7]

Answer:

Option A

They are located near the equator

Explanation:

From the diagram, we can observe that all the rain forest zones occur near the equator.

This is because on an annual basis, the equator receives the highest concentration of solar radiation in the whole Earth. This implies that the rate of evaporation of water from the water bodies present  is high, and consequently, the amount of rainfall is high also. This abundant sunshine and high rainfall  leads to the growth of the tropical rain forests at those regions

6 0
3 years ago
To convert from Mass A to moles of B in stoichiometry problems, the following steps are followed:
WINSTONCH [101]
I think a is the answer

6 0
4 years ago
An empty beaker weighs 20g and when filled with
Sphinxa [80]

Answer: The density of kerosene is 2.7g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of kerosene = mass of beaker with kerosene - mass of empty beaker = 60 g - 20 g = 40 g

Volume of kersone = 15cm^3

Putting in the values we get:

Density=\frac{40g}{15cm^3}

Density=2.7g/cm^3  

Thus the density of kerosene is 2.7g/cm^3

3 0
3 years ago
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