According to the research, scientific observations are important because every experiment begins with observations.
<h3>What are observations?</h3>
It consists of receiving knowledge of the outside world through our senses, it means that we naturally make observations about the world around us and the first step proposed by the scientific method.
Scientific observation, on the other hand, refers to the process of detailing any phenomenon of nature with analytical intent, usually later replicated in a laboratory (experimentation) or controlled environment.
Similarly, there are qualitative observations that are based on the senses, which are generally more subjective, while quantitative observations are more objective, focusing mainly on numbers, for example "the flower has five petals" is a quantitative observation.
Therefore, we can conclude that according to the context, scientific observations are important because every experiment begins with observations.
Learn more about scientific observations here: brainly.com/question/24071808
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Answer:
0.196 M
Explanation:
First, we have to calculate the moles of sodium hydroxide.
moles = mass / molar mass
moles = 3.9280 g / (39.997 g/mol) = 0.098207 mol
It is important to realize that even though 300 mL is the volume of water firstly added to dissolve the hydroxide, the flask is then filled to the mark, meaning that the volume of the solution is 500 mL = 0.500 L.
The molar concentration of sodium hydroxide is:
![M=\frac{n_{solute}}{V_{solution}(L)} =\frac{0.098207 mol}{0.500L} =0.196 M](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bn_%7Bsolute%7D%7D%7BV_%7Bsolution%7D%28L%29%7D%20%3D%5Cfrac%7B0.098207%20mol%7D%7B0.500L%7D%20%3D0.196%20M)
The concentration is an intensive property, that is, it does not depend on the amount of matter. As a consequence, the concentration of the 50 mL of solution in the buret is the same as the concentration in the flask.
d= 8/10 so yah that was a guess
Answer:
mass of oxygen gas in Kg = 15.0Kg
Explanation:
Volume of air in the room = 4.0m*5.0m*2.5m = 50m³
volume of oxygen in the room = 21/100 * 50m³ = 10.5m³
using the ideal gas equation; PV=nRT
number of moles of oxygen gas, n = PV/RT
At STP, P = 1atm, V = 10.5m³ = (10.5*1000)dm³ = 10500dm³, R = 0.082 atmdm³K⁻¹mol⁻¹, T = 273K
n = 1 * 10500/ (273 *0.082)
n = 469.04 moles
mass of oxygen gas in Kg = (no of moles * molar mass)/1000
molar mass of oxygen gas = 32g
mass of oxygen gas in Kg = (469.04 * 32)/1000
mass of oxygen gas in Kg = 15.0Kg
Answer:
4.716x10^25
Explanation:
1 molecule of water is equivalent to 6.02x10^23
hence 78.34 is equivalent to 78.34x6.02x10^23
and the answer is 4.716x10^25