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Pie
4 years ago
15

-9s - 8 = -4s + 8 - 3s

Mathematics
2 answers:
frozen [14]4 years ago
6 0
We move all terms to the left:

-9s-8-(-4s+8-3s)=0

We add all the numbers together, and all the variables

-9s-(-7s+8)-8=0

We get rid of parentheses

-9s+7s-8-8=0

We add all the numbers together, and all the variables

-2s-16=0

We move all terms containing s to the left, all other terms to the right

-2s=16

s=16/-2

s=-8
Olenka [21]4 years ago
4 0
I wont solve this because Im to lazy, but I do recommend some of these sites to help you with your problem. MathPapa Algebra Calculator and PhotoMath. Hope this helps.
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Step-by-step explanation:

4 0
4 years ago
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4 years ago
Which line is perpendicular to the line 3y=5x-1
Ainat [17]
For lines to be perpendicular their slopes have to be negative reciprocals of one another, mathematically...

m1*m2=-1...in this case:

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3 0
3 years ago
Can somebody help me
9966 [12]

Plot the intercepts:

y=-1

x=?

to find the x intercept, you dont solve the equation as it is solved in the slope-intercept form. instead, you simply plug in 0 for y:

0=1/4x-4

0=1/4x-4+4

4=1/4x

4/1/4=1/4x

1/4=0.25

x=16

revise:

y=(0, -1)

x=(16,0)

graph the slope for y=-1/2x-1: start from say point (0,-1)

graph the slope for y=1/4x-4: start from say point (16,0) ; you can just ise the intercept (0,-4) since the graph is diluted small...anyways

the points intersect at (4, -3) so thats the solution to the equations

NOTE: when graphing slopes that are negative either the numerator or the denominator can be graphed negative. so I graphed the first equation with the numerator as the positive and the denominator as the negative : rise= 1 ; run: -2. once i got to the end of the provided graph i started from the -1 y-intercept again and graphed the equation using: rise=-1; run=2

*graphing messes me up, too*

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4 years ago
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Answer:

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(d) 33,005565°

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3 years ago
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