Answer:
4$ for large 3$ for a small
Step-by-step explanation:
Answer:
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
Step-by-step explanation:
Originally Triangle has height =3.5cm and width=4cm
Beth enlarged the same triangle by scale of 5 and calculate area of triangle
The area of triangle as given as A= $$\frac{1}{2} \texrm{ (base) (height)}$$
Area of original triangle is A =$$\frac{1}{2}(3.5 \times 4)$$
Since, The triangle is enlarged by scale of 5
New height =3.5x5 = cm and new width=4x5cm
Area of new triangle is
A' = $$\frac{1}{2} (\textrm{new width} ) ( \textrm{new height})$$
A' = $$\frac{1}{2}(3.5 \times 5)(4\times 5)$$
A' = $$\frac{1}{2}(3.5 \times 4)(5^{2})$$
A' = $$A (5^{2})$$
Now, Looking what error beth made is:
Beth found Area of new triangle is A' = $$\frac{1}{2}(3.5)(4)(5)$$
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
11 students wore blue jeans
<h3><u>Solution:</u></h3>
Given that , For the choir concert, the choir director has asked that everyone either wears black pants or blue jeans.
Three times as many students wore either black pants as blue jeans.
Let the number of students who wore blue jeans be n.
Then the number of students who wore black pants will be 3n
Now if there are 44 students is choir, we have to find how many wore blue jeans
As total students = 44
Students with blue jeans + students with black pants = 44
n + 3n = 44
4n = 44
n = 11
So, 11 students wore blue pants.
Then, 3n = 3 x 11 = 33 students wore black pants.
Hence, 11 students wore blue jeans
Answer:
Domain: (-∞, ∞) or All Real Numbers
Range: (0, ∞)
Asymptote: y = 0
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Step-by-step explanation:
The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.
The range is from 0 to ∞. This where all values of y are defined.
An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.
The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Answer:
123.077
Step-by-step explanation:
0.39x=48
0.39x/0.39=48/0.39
x=48/0.39
x=123.077