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Yuri [45]
4 years ago
10

Find the standard form of the equation of the ellipse with the given characteristics and center at the origin. Foci: (±7, 0); ma

jor axis of length 18

Mathematics
1 answer:
n200080 [17]4 years ago
4 0

Answer: \dfrac{x^2}{81}+\dfrac{y^2}{32}=1

Step-by-step explanation:

The standard form of equation of ellipse with foci (±c,0) as:

\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1

, where major axis = 2a and minor axis = 2b

Given: Foci: (±7, 0); major axis of length 18

i.e. c= 7 and 2a =18 ⇒a= 9

Also,

c^2=a^2-b^2\Rightarrow\ b^2= a^2-c^2\\\\\Rightarrow\ b^2={9^2-7^2}={81-49}\\\\\Rightarrow\ b^2=32

Put value of a^2 and b^2 , we get the required equation :

\dfrac{x^2}{81}+\dfrac{y^2}{32}=1

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A circle has an area of 200.96 units2 and a circumference of 50.24 units. If the radius is 8 units, what can be said about the r
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Answer:

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Step-by-step explanation:

The area of a circle can be written as;

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The circumference of a circle is;

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Using the formula, w can derive the relationship between the two variables.

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Circumference = 50.24

Radius = 8

To confirm;

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A/C = 200.96/50.24

A/C = 4

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