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goldenfox [79]
2 years ago
12

How many times heavier is a 16 1/2 pound rockthen a 10 1/2 pound rock

Mathematics
2 answers:
Finger [1]2 years ago
5 0
A 16 1/2 pound rock is 6 more pounds heavier than a 10 1/2 pound rock.
Ann [662]2 years ago
5 0

Answer: 16\dfrac{1}{2} pound rock is 1.571 times heavier than 10\dfrac{1}{2} pounds rock.

Step-by-step explanation:

Since we have given that

Quantity of rock = 16\dfrac{1}{2}\ pounds=\dfrac{33}{2}\ pounds

Quantity of another rock = 10\dfrac{1}{2}=\dfrac{21}{2}\ pounds

We need to find the number of times heavier is 16 1/2 pound rockthen a 10 1/2 pound rock.

so, number of times is given by

\dfrac{33}{2}\div \dfrac{21}{2}\\\\=\dfrac{33}{2}\times \dfrac{2}{21}\\\\=\dfrac{33}{21}\\\\=1.571

Hence, 16\dfrac{1}{2} pound rock is 1.571 times heavier than 10\dfrac{1}{2} pounds rock.

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shusha [124]
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You enter a room. 2 dogs, 4 horses, one giraffe, and a duck are laying on a bed. 3 chicken are flying over a chair. How many leg
azamat

Answer:

28 legs are on the ground

8 0
1 year ago
Is this figure a polygon? Explain.
denis-greek [22]
Yes.

It’s a flat figure (2D), and all of its lines are connected with one another. There aren’t any open points/lines. It’s closed to create a shape. This means it’s a polygon.
3 0
1 year ago
Select the THREE equations that this diagram could represent.
Vladimir [108]

<u>Question </u>

Select the three equations that this diagram could represent.

<u>                                                                                                                                     </u>

<u>Answer</u>

<em>Well, we first have to find out what the diagram says.</em>

<em>So what the diagram says is that  18 + 18 + 18 = 54.</em>

<em>Given this information,  we have to figure what other answers = 54.</em>

<em>Therefore the answers are </em>

(A) 18 * 3 = 54.

(D) 54/18 = 3

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6 0
3 years ago
B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

8 0
2 years ago
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