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yarga [219]
3 years ago
6

Find the area of a parallelogram with base B and height H b = 87 cm h = 18.6 cm

Mathematics
2 answers:
kifflom [539]3 years ago
3 0
Area =hb
h=18.6
b=87
area=(18.6)(87)
a=1618.2 cm^2

S_A_V [24]3 years ago
3 0
The area would be 1618.2 cm. I think I am not positive.

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A manufacturer knows that their items have a normally distributed length, with a mean of 16.2 inches, and standard deviation of
statuscvo [17]

Answer:

57.926%

Step-by-step explanation:

Calculation for the probability that it is less than

16.4 inches long

Using this formula

z = (X - μ) / σ

Where,

X represent Date=16.4

μ represent Mean=16.2

σ represent Standard deviation=0.9 inches

Let plug in the formula

z = (16.4 - 16.2) /0.9 inches

z=0.2/0.9 inches

z = 0.2

Using Z-score table to find the area of 0.2

z=0.57926*100

z=57.926%

Therefore the probability that it is less than

16.4 inches long is 57.926%

6 0
3 years ago
The sum of two numbers is 11 and their product is 128. find the numbers?
KatRina [158]
X+y=11
xy=128
x=11-y, so (11-y)y=128
11y-y²=128
y²-11y+128=0
use the quadratic formula to find y: y=(11+√391i)/2 or y= (11-√391i)/2
x=(11-√391i)/2, or x=(11+√391i)/2

so either there is an error in your question, or you have two unreal numbers:
(11-√391i)/2 and (11+√391i)/2
5 0
3 years ago
A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam
Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Description in words of the parameter p

p represent the real population proportion of students who take notes

\hat p represent the estimated proportion of students who take notes

n is the sample size required  

z_{\alpha/2} represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Numerical estimate for p

In order to estimate a proportion we use this formula:

\hat p =\frac{X}{n} where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula  

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}  

For the 90% confidence interval the value of \alpha=1-0.90=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.64  

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

6 0
3 years ago
What is an extraneous solution? How does it arise in solving radical equations?
Yakvenalex [24]
I didn’t even know words at this point
3 0
3 years ago
Which line is perpendicular to a line that has a slope of -5/6?
svp [43]

Answer:

B

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m}

Given m = - \frac{5}{6}, then

m_{perpendicular} = - \frac{1}{-\frac{5}{6} } = \frac{6}{5}

Since m > 0 then lines LM and No are the 2 possible lines

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = L(- 5, - 3) and (x₂, y₂ ) = M(0, 3)

m = \frac{3+3}{0+5} = \frac{6}{5}

Hence the required line is LM

3 0
3 years ago
Read 2 more answers
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