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vampirchik [111]
4 years ago
7

The chart shows the bids provided by four contractors to complete a job.

Physics
1 answer:
serg [7]4 years ago
5 0

"Cost-effective" means "most economical", "lowest cost", "cheapest".

Joshua . . . charges $25 an hour, says the job will take him 5 hours.  If Joshua is hired, then the total cost to get the job done is ($25/hr) x (5 hr) = <em>$125</em> .

Carmen . . .  $20 per hour, 7 hours, total cost ($20/hr) x (7 hr) = $140

Dante . . . $30 per hour, 6 hours, total cost ($30/hr) x (6 hr) = $180

Alicia . . .  $20 per hour, 8 hours, total  cost ($20/hr) x (8 hr) = $160

<em>Joshua's</em> total bid cost is the lowest, so his company should get the job.

Notice that all of these bids are predictions of something that hasn't happened yet.  <u><em>IF</em></u> Joshua can actually finish the job in 5 hours, like he says, then he would be the cheapest.  But his estimate of the time required is the shortest of all.  That's great if he's done this kind of job before.  But if he doesn't have experience doing it, I would be a little careful.  He could get part of the way through the job and discover that it's going to take him longer than he thought.

There are also certain regional considerations:

-- I live in Chicago, where cost is not always the main factor.  Here, you would have to award the job to Dante, because his brother supplies the concrete in the ward where the job will be done, and his niece is dating the alderman of that ward.

-- In California, you'd have to give Alicia the job because the board of directors and management of her company are all women.  You should also plan to provide chocolates, flowers, and college scholarships to her administrative staff and IT department relatively soon after the job is completed.

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lapo4ka [179]

Answer:

      K =  \frac{h'}{8 m  \ \Delta x^2}K

Explanation:

The Heisenberg uncertainty principle is

          Δx Δp ≥ h' / 2

          h’ =\frac{h}{2\pi }

The kinetic energy of a particle is

          K = ½ m v²

           p = mv

           v = \frac{p}{m}

substitute

           K = \frac{1}{2}  \frac{p^2}{m}

from the uncertainty principle,

           Δp = \frac{h'}{2 \ \Delta x}

we substitute

          K = \frac{1}{2m} ( \frac{h'}{2 \ \Delta x})^2

          K =  \frac{h'}{8 m  \ \Delta x^2}

4 0
3 years ago
In the diagram, q1 = -6.39*10^-9 C and q2 = +3.22*10^-9 C. What is the electric field at point P? pls help
Alexxx [7]

Answer:

Below

Explanation:

First draw the vectors that represent both electric fields.

E1 is the elictric field created by q1, E2 is the one created by q2.

● q1 is negative so E1 will point from P.

● q2 is positive so E2 will point out of P

(Picture below)

■■■■■■■■■■■■■■■■■■■■■■■■■■

The resulting electric field is equal to the sum of the two fields since both vectors are colinear.

Let E be the total field.

● E = E1 + E2

The formula of the electric field intensity is:

● E = K ×(q/d^2)

-K is Coulomb's constant

-d is the distance between the charge and the object ( here P)

-q is the charge

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E1 = K × (q1/d1^2)

The distance between q1 and P is the qum of 0.15 m 0.25 m. (0.4 m)

Coulombs constant is 9×10^9 m^2/C^2

● E1 = 9×10^9 ×[-6.39 × 10^(-9)/ 0.4^2]

● E1 = -359.43 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E2 = K ×(q2/d^2)

The distance between q2 and P is 0.25 m.

● E2 = 9×10^9×[3.22×10^(-9) /0.25^2]

● E2 = 463.68 N/C

■■■■■■■■■■■■■■■■■■■■■■■■■■

● E = E1 + E2

● E = -359.43+463.68

● E = 105.25 N/C

4 0
3 years ago
Read 2 more answers
How much work did the movers do (horizontally) pushing a 43.0-kg crate 10.4 m across a rough floor without acceleration, if the
Ilia_Sergeevich [38]

The crate is in equilibrium. Newton's second law gives

∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0

∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0

where

• <em>n</em> = magnitude of the normal force

• <em>mg</em> = weight of the crate

• <em>p</em> = mag. of push exerted by movers

• <em>f</em> = mag. of kinetic friciton, with <em>f</em> = 0.60<em>n</em>

<em />

It follows that

<em>p</em> = <em>f</em> = 0.60<em>mg</em> = 0.60 (43.0 kg) <em>g</em> = 252.84 N

so that the movers perform

<em>W</em> = <em>p</em> (10.4 m) ≈ 2600 J

of work on the crate. (The <em>total</em> work done on the crate, on the other hand, is zero because the net force on the crate is zero.)

8 0
4 years ago
In an elastic collision momentum is conserved as is
zzz [600]

In an elastic collision momentum is conserved as well as the kinetic energy

Explanation:

In physics, there are two types of collisions:

  • Elastic collision: in an elastic collision, the total momentum of the system is  conserved, and the total kinetic energy of the system is conserved as well. This is because there are no internal frictions acting on the system, so the energy is conserved. An example of elastic collision is (approximately) that occurring between two billiard balls.
  • Inelastic collision: in an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not. In fact, due to the presence of internal frictions, part of the total energy is converted into thermal energy and sound during the collision, and therefore "wasted", so the final total kinetic energy is less than the initial one. An example of inelastic collision is the collision between two cars. The maximum amount of kinetic energy is lost when the two objects stick together after the collision; in this case, we talk about perfectly inelastic collision.

Therefore, the complete sentence is

In an elastic collision momentum is conserved as well as the kinetic energy

Learn more about collisions:

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brainly.com/question/6439920

#LearnwithBrainly

7 0
3 years ago
An electric heater draws 13 amperes of current when connected to 120 volts. If the price of electricity is $0.10/kWh, what would
alexandr402 [8]

Answer:

C $0.75 my friend I wish it is right answer

6 0
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