Answer:
solution given:
acceleration (a)=?
initial velocity (u)=3m/s
final velocity (v)=6m/s
distance (s)=90m
we have
v²=u²+2as
substituting value
6²=3²+2*a*90
36=9+180a
36-9=180a
a=25/180
<u>a=0.1388m/s²</u>
Answer:
2.73×10¯³⁴ m.
Explanation:
The following data were obtained from the question:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Wavelength (λ) =?
Next, we shall determine the energy of the ball. This can be obtained as follow:
Mass (m) = 0.113 Kg
Velocity (v) = 43 m/s
Energy (E) =?
E = ½m²
E = ½ × 0.113 × 43²
E = 0.0565 × 1849
E = 104.4685 J
Next, we shall determine the frequency. This can be obtained as follow:
Energy (E) = 104.4685 J
Planck's constant (h) = 6.63×10¯³⁴ Js
Frequency (f) =?
E = hf
104.4685 = 6.63×10¯³⁴ × f
Divide both side by 6.63×10¯³⁴
f = 104.4685 / 6.63×10¯³⁴
f = 15.76×10³⁴ Hz
Finally, we shall determine the wavelength of the ball. This can be obtained as follow:
Velocity (v) = 43 m/s
Frequency (f) = 15.76×10³⁴ Hz
Wavelength (λ) =?
v = λf
43 = λ × 15.76×10³⁴
Divide both side by 15.76×10³⁴
λ = 43 / 15.76×10³⁴
λ = 2.73×10¯³⁴ m
Therefore, the wavelength of the ball is 2.73×10¯³⁴ m.
Answer:
The final acceleration becomes (1/3) of the initial acceleration.
Explanation:
The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :
m = mass
a = acceleration
According to given condition, if the mass of a sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.
Let a' is the final acceleration,
m' = 3m
So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.
Answer:
IT IS HOSPITAL OR AMBULANCE
SOME THING LIKE THAT IS WRITTEN ZOOM THAT PHOTO MORE
Answer:
The gravitational potential energy of the two-sphere system just as B is released is
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Explanation:
The gravitational potential energy of two masses (m and M), separated by a distance, d, is given as
U = -(GMm/d)
For our question,
Mass of object 1 = MA
Mass of object 2 = MB
Distance between them = x₁
U = -[(G)(MA)(MB)/x₁]
where G = Gravitational constant
G = (6.7 × 10⁻¹¹) Nm²/kg²
Hope this Helps!!!
