Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
Answer:
8
Step-by-step explanation:
3,4,5 and 6,_,10 are similar. what do you notice between the two? 6 is twice of 3. 10 is twice of 5. so then 4 would be half of 8.
hope i helped ;)
I think it is x > 5 because if you combine like terms you would get 2x-4>6 then you add 4 To 6 which is 10 then you do 10÷2 which is 5
Okay. Basically, a is greater than or equal to 9.
First, you do distribute the 2.
8a+2-10a(< or =)20
Subtract two on both sides.
8a-10a(< or =)18
Then subtract 10a from 8a
-2a(< or =)18
Divide by two on both sides
and switch around the greater than sign since you divided by a <span>-2
</span>a(> or =)-9
<span>And if you check, -9 works, -8 works, and -10 doesn't work.</span>