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3 years ago

5

Emma claims: Tomorrow it will either rain or not rain. The probability that it will rain is 0.5. Is she correct? Explain your an

swer fully.

1 answer:

Stella [2.4K]3 years ago

3 0

Yes, there is a 50% chance it will rain. This leaves the other 50% chance to be that it will not rain. This fills up 100% of the possibilities. It is only logical that it will either rain or it won't, there is no third option.

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A store is having a sale where everything is discounted 30% find the discount and the sales price of a customer buys an item tha

professor190 [17]

Discount = 365*30/100 = $109.5

sales price = 365*70/100 = $255.5

Did you understand?

5 0

3 years ago

Read 2 more answers

Identify the ratio of males to female students in 2009

seraphim [82]

Answer:

0.8

Step-by-step explanation:

<em><u>Attached is the graph for the question.</u></em>

<em><u /></em>

To find the ratio of male to female students in 2009, we first need to know the number of male students and the number of female students.

Looking at the bars of 2009, we can say:

Male students are roughly around 7800

Female students are roughly around 10,800

The ratio is 7800/10,800 = 0.722

From the answer choices, we take the closest estimate, 0.8

That is the answer.

3 0

3 years ago

What is the square root of 46?

Kazeer [188]

If you estimate
7 times 7=49 so the square root of 46 is less than 7
6 times 6= 36 so the square root of 46 is more than 6
so if you do it on a calculator the answer is 6.78

8 0

3 years ago

Read 2 more answers

Choose the solution to this inequality. < 3 34 O A. y. -12 B. ys o o c. y< 1 / 3 O D. y> 4

Rasek [7]

Answer:

$\boxed{\boxed{\bf y < - \cfrac{1}{2}}}$

<u>Option A</u>

Step-by-step explanation:

$\bf \: Given \: inequality :$

$\sf \implies \: \cfrac{4}{3 } \: y < \cfrac{ - 8}{3} \: y$

We need to find the solution to the inequality.

$\bf \: Solution:$

$\sf \implies \: \cfrac{4}{3 } \: y < \cfrac{ - 8}{3} \: y$

$\rm \: Firstly,Flip \: the \: inequality :$

$\sf \implies \cfrac{ - 8}{3} y > \cfrac{4}{3}$

$\rm \: Then,\; multiply\; each\: side \: \: by \: \cfrac{ - 3}{8} \: :$

$\sf \implies \: \cfrac{ - 8}{3}y \times \cfrac{ 3}{ - 8} > \cfrac{4}{3} \times \cfrac{ 3}{ - 8}$

$\rm \: Use \: cancellation \: method \: to \: cancel \: LHS:-$

<u>Steps </u><u>of </u><u>cancelling :-</u>

<em>Cancel -8( which is on the numerator) and -8 (on the denominator) :</em>

$\sf \implies \cfrac{ \cancel{- 8}}{3}y \times \cfrac{ 3}{ \cancel{- 8} } > \cfrac{4}{3} \times \cfrac{ 3}{ - 8}$

<em>Cancel 3(which is on the numerator)</em><em> </em><em>and 3( which is on the denominator)</em><em> </em>:

$\sf \implies\cfrac{ \cancel{- 8}}{ \cancel3}y \times \cfrac{ \cancel 3}{ \cancel{- 8} } > \cfrac{4}{3} \times \cfrac{ 3}{ - 8}$

<em>Results to,</em>

$\sf \implies \: 1y < \cfrac{4}{3} \times \cfrac{3}{ - 8}$

<em>As we know 1y equals to y.</em><em> </em>So,

$\sf \implies \: y < \cfrac{4}{3} \times \cfrac{3}{ - 8}$

$\rm \: Now, Cancel \: the \: RHS :$

<u>Steps </u><u>of</u><u> cancelling:-</u>

<em>Cancel 3 (which is on the numerator) and cancel 3 (which is on the denominator)</em><em>:</em>

$\sf \implies \: y < \cfrac{4}{ \cancel3} \times \cfrac{ \cancel3}{ - 8}$

$\sf \implies{y} < 4 \times \cfrac{1}{ - 8}$

<em>Cancel 4 and -8 </em><em> </em><em>:</em>

$\sf \implies \: y < \cancel{4} \times \cfrac{1}{ \cancel{ - 8}}$

<em>Results to,</em>

$\sf \implies \: y < 1 × \cfrac{ - 1}{2}$

$\sf \implies \: y < \cfrac{ - 1}{2}$

$\rm \: Which \: can \: be \: rewritten \: as,$

$\sf \implies \: y < - \cfrac{1}{2}$

This matches with option A.

Hence, Option A is correct!

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.I am joyous to help!

7 0

3 years ago

A movie theater sold 1000 tickets and made 7160 in one night if an adult ticket cost 9 and children's ticket cost 5 how many adu

11Alexandr11 [23.1K]

If all adult tickets were sold, it would be 9000The difference between an adult ticket and a child ticket is 4
9000-7160 = 1840
1840/4 = 460 = no. of childs tickets1000 - 460 = 540 = no. of adults tickets

7 0

3 years ago