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Alexus [3.1K]
3 years ago
8

What is the approximate distance between points P and Q? Round your answer to the nearest hundredth.

Mathematics
2 answers:
Debora [2.8K]3 years ago
6 0
The approximate distance between point p and q are 5.1 so the answer is D.
Elodia [21]3 years ago
5 0

Answer:

(D) 5.1 units

Step-by-step explanation:

From the given graph, we get the two points P and Q that are:

P=(-3,-4) and Q=(2,-3)

Thus, the approximate distance between the points P and Q is given as:

|PQ|=\sqrt{(-3+4)^4+(2+3)^2}

|PQ|=\sqrt{(1)^2+(5)^2}

|PQ|=\sqrt{1+25}

|PQ|=\sqrt{26}

|PQ|=5.1 units

Therefore, the approximate distance between the points P and Q is 5.1 units.

Hence, option (D) is correct.

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First rewrite 8/25 and 7/20 so that they have a common denominator
Pie

Answer:

  • 8/25 = 32/100
  • 7/20 = 35/100

Step-by-step explanation:

25 and 20 have a least common multiple of 100, so that is your least common denominator.

  8/25 = (8·4)/(25·4) = 32/100

  7/20 = (7·5)/(20·5) = 35/100

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Two different simple random samples are drawn from two different populations. The first sample consists of 30 people with 16 hav
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Answer:

  • There is no significant evidence that p1 is different than p2 at 0.01 significance level.
  • 99% confidence interval for p1-p2 is  -0.171 ±0.237 that is (−0.408, 0.066)

Step-by-step explanation:

Let p1 be the proportion of the common attribute in population1

And p2 be the proportion of the same common attribute in population2

H_{0}: p1-p2=0

H_{a}: p1-p2≠0

Test statistic can be found using the equation:

z=\frac{p2-p1}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

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  • p2 is the sample proportion of the common attribute in population2 (\frac{1337}{1900} =0.704)
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  • n1 is the sample size of the people from population1 (30)
  • n2 is the sample size of the people from population2 (1900)

Then z=\frac{0.704-0.533}{\sqrt{{0.701*0.299*(\frac{1}{30} +\frac{1}{1900}) }}} ≈ 2.03

p-value of the test statistic is  0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.

99% confidence interval estimate for p1-p2 can be calculated using the equation

p1-p2±z*\sqrt{\frac{p1*(1-p1)}{n1}+\frac{p2*(1-p2)}{n2}} where

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Thus 99% confidence interval is

0.533-0.704±2.58*\sqrt{\frac{0.533*0.467}{30}+\frac{0.704*0.296}{1900}} ≈ -0.171 ±0.237 that is (−0.408, 0.066)

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