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Alexus [3.1K]
3 years ago
8

What is the approximate distance between points P and Q? Round your answer to the nearest hundredth.

Mathematics
2 answers:
Debora [2.8K]3 years ago
6 0
The approximate distance between point p and q are 5.1 so the answer is D.
Elodia [21]3 years ago
5 0

Answer:

(D) 5.1 units

Step-by-step explanation:

From the given graph, we get the two points P and Q that are:

P=(-3,-4) and Q=(2,-3)

Thus, the approximate distance between the points P and Q is given as:

|PQ|=\sqrt{(-3+4)^4+(2+3)^2}

|PQ|=\sqrt{(1)^2+(5)^2}

|PQ|=\sqrt{1+25}

|PQ|=\sqrt{26}

|PQ|=5.1 units

Therefore, the approximate distance between the points P and Q is 5.1 units.

Hence, option (D) is correct.

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Answer:

s= bt - c + 25t +abr

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Step-by-step explanation:


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4 years ago
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A graphing calculator can be helpful for these.

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4 years ago
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Suppose that one pe
ElenaW [278]

Answer:

The probability that someone who tests positive has the genetic disease is approximately 0.166 or 16.6% who tests positive actually has the disease

Step-by-step explanation:

The number of persons in 10,000 people that have the disease = One

The percentage of people with the disease that test positive = 99.6%

The percentage of people who do not have the disease test positive = 0.05%

The probability that someone who tests positive has the genetic disease

P(disease | positive) = \dfrac{P(disease) \cdot P(positive | disease)}{P(disease) \cdot P(positive | disease) + P(nodisease) \cdot P(positive | nodisease)}

P(disease) = 0.01% = 0.0001

P(positive disease)  = 99.6% = 0.996

P(nodisease) = (10,000,000 - 100)/10,000,000 = 99.99% = 0.9999

P(positivenodisease) = 0.05% = 0.0005

Whereby 10,000,000 people are tested, 1000 out of the 1,000,000 will have the disease, 1,000 - 0.996 × 1000 = 4 people out of the 1,000 will test negative while 996 will test positive. From the 9,999,000 people who do not have the disease, 9,999,000 × 0.0005 = 4999.5 will give positive test results.

Therefore, the total number of people that tests positive = 4,999.5 + 996 = 5,995.5

Therefore, out of the 5,995.5 that test positive for the disease, 996 will test positive

The probability that someone who tests positive has the genetic disease, P(disease positive) = 996/5,995.5 ≈ 0.166 or 16.6%

Therefore, approximately 16.6% of the people that test positive for the disease actually has the disease

We have;

P(disease | positive) = \dfrac{0.0001 \times 0.996}{0.0001 \times 0.996 + 0.9999 \times 0.0005} = 0.16612459344

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