Question

Point A is at (-2,4) and point C is at (4,7). Find the coordinates of point B on AC such that the ratio of a B to a C is 1:3

Answer 1

Answer:

$[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]$

$[x=\frac{4-6}{4}, y=\frac{7+12}{4}]$

$[x=\frac{-2}{4}, y=\frac{19}{4}]$

$[x=-0.5, y=4.75]$

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).

Step-by-step explanation:

We have been given that point a is at   (-2,4) and point c is at   (4,7) .

We are asked to find the coordinates of point b on segment ac such that the ratio is 1:3.

We will use section formula to solve our given problem.

When point P divides a segment internally in the ratio m:n, the coordinates of point P would be:

$[x=\frac{mx_2+nx_1}{m+n}, y=\frac{my_2+ny_1}{m+n}]$

$\texttt{Let point} (-2,4)=(x_1,y_1) \texttt {and point} (4,7)=(x_2,y_2).$

$[x=\frac{1(4)+3(-2)}{1+3}, y=\frac{1(7)+3(4)}{1+3}]$

$[x=\frac{4-6}{4}, y=\frac{7+12}{4}]$

$[x=\frac{-2}{4}, y=\frac{19}{4}]$

$[x=-0.5, y=4.75]$

Therefore, the coordinates of point 'b' would be (-0.5 , 4.75).