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3241004551 [841]

1 year ago

9

Paloma has 3 jackets, 6 scarves, and 4 hats. What is the number of different outfits consisting of a jacket, a scarf, and a hat

that Paloma can wear?
Answer:
Submit Answer

1 answer:

Charra [1.4K]1 year ago

5 0

Answer:

72

Step-by-step explanation:

We need to multiply all of them because there are 3 choices for jackets, 6 for scarves and so on.

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3 years ago

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Alex777 [14]

2x+4.7=77.8

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an isosceles triangle contains two equal angles. Each of these angles is 25 degrees larger than twice the smallest angle. What a

Helga [31]

Well, the sum of all internal angles in a triangle, isosceles or whatever else, is always 180°, so the sum of all those three folks, will be 180 then

so.. hmmm let's say the smallest angle is "a" units

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so... the other two twin angles, are 2a+25 each

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3 years ago

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Oksana_A [137]

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3 years ago

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A survey was conducted of 42 students who take math, Eng lish, or history. In the survey, 15 students said they take math and hi

strojnjashka [21]

Answer:

16 students take only English or only Math.

Step-by-step explanation:

We can solve this problem by treating these values as sets, and building the Venn Diagram.

I am going to say that:

A is the number of students who take Math.

B is the number of students who take English.

C is the number of students who take History.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that only take Math, $A \cap B$ is the number of students who take both Math and English, $A \cap C$ is the number of students that take both Math and History, and $A \cap B \cap C$ is the number of students that take all these classes.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)$

There were 42 students suveyed. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42$

We start finding the values from the intersection of three sets.

12 students said they take math, English, and history. This means that:

$A \cap B \cap C = 12$

18 students said they take English and history. This also takes into account those who take math, english and history. So:

$(B \cap C) + (A \cap B \cap C) = 18$

$B \cap C = 6$

17 students said they take math and English.

$(A \cap B) + (A \cap B \cap C) = 17$

$A \cap B = 5$

15 students said they take math and history

$(A \cap C) + (A \cap B \cap C) = 15$

$A \cap C = 3$

2 students said they only take history.

$c = 2$

How many students take only English or only math?

This is a + b, that we can find by the following formula:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = 42$

$a + b + 2 + 5 + 3 + 6 + 12 = 42$

$a + b = 16$

16 students take only English or only Math.

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3 years ago