Answer:
x = 4√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Trigonometry</u>
- Pythagorean Theorem: a² + b² = c²
Step-by-step explanation:
<u>Step 1: Define</u>
We are given a right triangle. We can use Pythagorean Theorem.
a = 19
b = x
c = 21
<u>Step 2: Find </u><em><u>x</u></em>
- Substitute: 19² + x² = 21²
- Isolate <em>x</em> term: x² = 21² - 19²
- Evaluate: x² = 441 - 361
- Subtract: x² = 80
- Isolate <em>x</em>: x = √80
- Simplify: x = 4√5
And we have our final answer!
for an isosceles right triangle the legs would be 2 times the square root of the hypotenuse
so for this:
the legs would be 2sqrt(10)
Answer:
125
Step-by-step explanation:
Answer:
For Lin's answer
Step-by-step explanation:
When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.
Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.
Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.
Answer:
64 textbooks
Step-by-step explanation:
the first two teachers had 21 students each that's 21+21=42
the other teacher had 22 students so apparently all the textbooks handed to the students are,21+21+22=64
