Ya, calculus and related rates, such fun!
everything is changing with respect to t
altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min
area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min
base=db/dt
alright
area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt
ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b
so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min
therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt
the base is decreasing at 1.6cm/min
Answer:
6x-108
Step-by-step explanation:
-3 · 2(7 · 2 - x + 4)
= ((−3)(2))((7)(2) +− x + 4)
= −84 + 6x − 24
= 6x − 108
The answer is 6x - 108
61.
40 ==> 100 %
x ==> 15 %
15*40/100 = 6.
Therefore, merely 6 students received C grades.
62.
23 500 ==> 100%
x ==> 42 %
42*23500/100 = 9870
Therefore 9870 people in the town are over 45 years of age.
You continue wth this method and you'll find for the 63, 64, 65.
In maths, you have to understand what you're doing dude ^^.
Whatever the answer for 64 and 65 are
64.
21.50*20/100 = 4.3
65.
250 ==> 100 %
45 ==> x %
x = 45*100/250 = 18 %
i will let you do the 63 alone, give me what you have found in the comments, i'll verify your answer.
Hope this helps !
Photon
Answer:
Quadrant II
Step-by-step explanation:
Below will be a picture provided to show you which quadrants are in a coordinate grid.
To graph (-4, 1) we will start at the origin, go 4 units to the left and 1 unit up.
As you can see in the image, it will be plotted in quadrant 2.
Best of Luck!
<h3>Assumption:</h3>
let the number be x, so that the two numbers are x and x - 32
<h3>Solution:</h3>
x + x - 32 = 92
or, 2x = 92 + 32
or, 2x = 124
or, x = 124/2 = 62
<h2>Answer:</h2>
The first number is x = <u>62.</u>
The second number is x - 32 = 62 - 32 = <u>30</u><u>.</u>
