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Volgvan
3 years ago
13

A 1500-W heater is connected to a 120-V line. How much heat energy does it produce in 2.0 hours? Hint: how are power and energy

related?
Physics
1 answer:
ELEN [110]3 years ago
3 0
Power is the rate of work done or produced by a system. It will have units of Watts which is equivalent to Joules per second. To determine the work or energy produced by the system, we multiply power with time. We do as follows:

Energy = Power x time
Energy = 1500 J/s (2.0 hr) (3600 s / 1 hr) 
Energy = 10800000 J
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What is the kinetic energy of a 0.135 kg baseball thrown at 40 m/s
Ronch [10]
KE = 1/2 * m * v^2
KE = 1/2 * 0.135 * 40^2
KE = 1/2 * 0.135 * 1600
KE = 108 J
4 0
3 years ago
Which one of the following statements concerning the Stefan-Boltzmann equation is correct? The equation can be used to calculate
Helen [10]

"The equation can be used to calculate the power absorbed by any surface" statement concerning the Stefan-Boltzmann equation is correct.

Answer: Option A

<u>Explanation:</u>

According to Stefan Boltzmann equation, the power radiated by black body radiation source is directly proportionate to the fourth power of temperature of the source. So the radiation transferred is absorbed by another surface and that absorbed power will also be equal to the fourth power of the temperature. So the equation describes the relation of net radiation loss with the change in temperature from hotter temperature to cooler temperature surface.  

                            P=e \sigma A\left(T^{4}-T_{c}^{4}\right)

So this law is application for calculating power absorbed by any surface.

4 0
3 years ago
The temperature of the cooling water as it leaves the hot engine of an automobile is 240 °F. After it passes through the radiato
djverab [1.8K]

Answer:571.09 kJ

Explanation:

Given

Temperature of cooling water from engine exit=240^{\circ} F\approx 115.55^{\circ}C

After Passing through the radiator its temperature decreases to 175^{\circ}F\approx 79.44^{\circ}F

specific heat of water=4.184 J/g^{\circ}C

Volume of water = 1 gallon\approx 3.78 L

density of water \rho =1 gm/mL

Thus mass of water=\rho \times V=3.78\times 1=3.78 kg

Heat transferred to the surrounding is equal to heat absorbed by cooling water

Q=m\cdot c\cdot \Delta T

Q=3.78\times 4.184\times 1000\times (115.55-79.44)

Q=3.78\times 4.184\times 1000\times (36.11)

Q=571.09 kJ

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3 years ago
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Fiesta28 [93]

Explanation:

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7 0
3 years ago
Bridget is riding her bicycle up a hill. Which statements are correct? Select five options.
Flura [38]

Answer:

A,B,C,D, and F are correct

Explanation:

5 0
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