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3 years ago

A car traveling 13 m/s to the north collides with a car traveling 19 m/s to the

Physics

2 answers:

Sveta_85 [38]3 years ago

4 0

The answer should be 16,250 kg- m/s

mamaluj [8]3 years ago

4 0

Answer: 0kg(m/s)

Explanation:

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Last night, Shirley worked on her accounting homework for one and one half hours. During that time, she completed 6 problems. Wh

hodyreva [135]

Answer:

velocity in problems per hour = 4 per hour

so correct option is b. 4 per hour

Explanation:

given data

worked on homework time = 1.5 hour

completed = 6 problems

to find out

What is the velocity in problems per hour

solution

we know that Shirley solve complete 6 accounting homework problem in 1.5 hour so her velocity in problems per hour will be as

velocity in problems per hour = $\frac{complete\ problem}{time\ taken}$ ..................1

put here value we will get

velocity in problems per hour = $\frac{6}{1.5}$

velocity in problems per hour = 4 per hour

so correct option is b. 4 per hour

3 0

3 years ago

Read 2 more answers

On a frictionless track,cart 1 is moving with a constant,rightward(+) velocity of 1.0m/s.Cart 2 is also moving rightward with co

mamaluj [8]

Answer:

The final velocity of cart 1 is 3m/s

Explanation:

From principle of conservation of linear momentum, which states that sum of the momentum before collision is equal to the sum of the momentum after collision.

Momentum, P is given as mass x velocity.

ΔP = Δmv = m₁u₁ +m₂u₂ = m₁v₁ + m₂v₂

Assumptions:

If the two carts are moving on frictionless track, then limiting frictional forces due to their weights are negligible.

After the elastic collision, the two carts will move separately with different velocity

u₁ + u₂ = v₁ + v₂;

where;

u₁ and u₂ are the initial velocity for cart 1 and cart 2 respectively

v₁ and v₂ are the final velocity for cart 1 and cart 2 respectively

1 m/s + 5 m/s = v₁ + 3m/s

6 m/s = v₁ + 3m/s

v₁ = 6 m/s - 3m/s = 3m/s

Therefore, the final velocity of cart 1 is 3m/s

4 0

3 years ago

What is a wave called that moves up and down

charle [14.2K]

Transverse waves is what its called

7 0

4 years ago

Read 2 more answers

In each cycle, a heat engine an input of 1940 J of heat and exhausts 1480 J of heat. What is the thermal efficiency?

AleksAgata [21]

Answer:

0.237 (23.7 %)

Explanation:

The thermal efficiency of an engine is given by:

$\eta=\frac{W}{Q_{in}}$

where

W is the useful work output of the engine

$Q_{in}$ is the heat in input

Here we have:

$Q_{in}=1940 J$

and the work done is the total heat in input minus the heat exhausted:

$W=1940 J - 1480 J=460 J$

So, the efficiency is

$\eta=\frac{460 J}{1940 J}=0.237$ (23.7 %)

8 0

3 years ago

A discus thrower turns with angular acceleration of 50 rad/s2, moving the discus in a circle of radius 0.80m. Find the radial an

anyanavicka [17]

Answer:

The value of tangential acceleration $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

The value of radial acceleration $\alpha_{r} = 80 \frac{m}{s^{2} }$

Explanation:

Angular acceleration = 50 $\frac{rad}{s^{2} }$

Radius of the disk = 0.8 m

Angular velocity = 10 $\frac{rad}{s}$

We know that tangential acceleration is given by the formula $\alpha_{t} =$ $r \alpha$

Where r = radius of the disk

$\alpha$ = angular acceleration

⇒ $\alpha_{t} =$ 0.8 × 50

⇒ $\alpha_{t} =$ 40 $\frac{m}{s^{2} }$

This is the value of tangential acceleration.

Radial acceleration is given by

$\alpha_{r} = \frac{V^{2} }{r}$

Where V = velocity of the disk = r $\omega$

⇒ V = 0.8 × 10

⇒ V = 8 $\frac{m}{s}$

Radial acceleration

$\alpha_{r} = \frac{8^{2} }{0.8}$

$\alpha_{r} = 80 \frac{m}{s^{2} }$

This is the value of radial acceleration.

7 0

4 years ago