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Goryan [66]
3 years ago
6

A car traveling 13 m/s to the north collides with a car traveling 19 m/s to the

Physics
2 answers:
Sveta_85 [38]3 years ago
4 0
The answer should be 16,250 kg- m/s
mamaluj [8]3 years ago
4 0

Answer: 0kg(m/s)

Explanation:

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A water hose is used to fill a large cylindrical storage tank of
ludmilkaskok [199]

Answer:

maximum possible speed by solving above equation for 7D is

v_{max} = \sqrt{\frac{49}{5}gD}

minimum possible value of speed for solving x = 6D is given as

v_{min} = \sqrt{9gD}

Explanation:

Let the nozzle of the hose be at the origin. Then the nearest part of the rim of the tank is at (, ) =  (6, 2) and the furthest part of the rim is at (, ) = (7, 2).

The trajectory of the water can be found as follows:

x = (v_o cos45) t

y =  (v_o sin45) t - \frac{1}{2}gt^2

Now from above two equations we have

y = x - \frac{gx^2}{v_o^2}

now we know that height of the cylinder is 2D so we have

x - \frac{gx^2}{v_o^2} = 2D

by solving above equation we have

x = \frac{v_o^2 \pm v_o^2\sqrt{1 - \frac{8gD}{v_o^2}}}{2g}

now we know that maximum value of x is 7D

so the maximum possible speed by solving above equation for 7D is

v_{max} = \sqrt{\frac{49}{5}gD}

minimum possible value of speed for solving x = 6D is given as

v_{min} = \sqrt{9gD}

6 0
3 years ago
If Q = 16 nC, a = 3.0 m, and b = 4.0 m, what is the magnitude of the electric field at point P?
Lynna [10]
In BPC

tan\theta =a/b = 3/4

\theta = tan^-1(0.75)

\theta = 36.87 deg

BP = sqrt(a^2 + b^2) = sqrt((3)^2 + (4)^2) = 5 m

Eb = k Q/BP^2 = (9 x 10^9) (16 x 10^-9)/5^2 = 5.76 N/C

Ea = k Q/AP^2 = (9 x 10^9) (16 x 10^-9)/4^2 = 9 N/C

Ec = k Q/CP^2 = (9 x 10^9) (16 x 10^-9)/3^2 = 16 N/C

Net electric field along X-direction is given as

Ex = Ea + Eb Cos36.87 = (9) + (5.76) Cos36.87 = 13.6 N/C

Net electric field along X-direction is given as

Ey = Ec + Eb Sin36.87 = (16) + (5.76) Sin36.87 = 19.5 N/C

Net electric field is given as

E = sqrt(Ex^2 + Ey^2) = sqrt((13.6)^2 + (19.5)^2) = 23.8 N/C
8 0
3 years ago
What cells in the nervous signals travel through the nervous system
kirill115 [55]

Answer:Although the nervous system is very complex, nervous tissue consists of just two basic types of nerve cells: neurons and glial cells Neurons are the structural and functional units of the nervous system They transmit electrical signals, called nerve impulses. Glial cells provide support for neurons.

Explanation:

3 0
3 years ago
Read 2 more answers
An 30-turn coil has square loops measuring 0.341 m along a side and a resistance of 3.61 Ω. It is placed in a magnetic field tha
Verdich [7]

Answer:

Thus, the induced current in the coil at t =1.73s is 9.98 A.

Explanation:

Faraday's law says

$\varepsilon = N \frac{d \Phi_B}{dt} $

where N is the number of turns and \Phi_B is the magnetic flux through the square coil:

Now,

N = 30

\theta = 37.5^o

A = (0.341m)^2= 0.11623m^2

B = 1.45t^3;

therefore,

$\varepsilon = N \frac{d \Phi_B}{dt}  = N\frac{d ( BA\:cos(\theta))}{dt}  = 30*\frac{d ( (1.45t^2)(0.1163)\:cos(37.5^o))}{dt}$

=30*(0.1163)\:cos(37.5^o)*1.45*\dfrac{d ( t^3)}{dt}  = 12.04t^2

\boxed{\varepsilon = 12.04t^2}

is the emf induced in the coil.

Now, the loop is connected to R = 3.61\Omega resistance; therefore, at t = 1.73s

\varepsilon = RI = 12.04t^2

RI = 12.04(1.73)^2

RI = 36.03

I = \dfrac{36.03}{3.61\Omega }

\boxed{I = 9.98A }

Thus, the current in the coil at t =1.73s is 9.98 A.

8 0
4 years ago
Why a male who has undergone a vasectomy would be unable to impregnate a female
irina [24]
A vasectomy disables a man in making sperm so therefore would not be able to impregnate I woman
6 0
3 years ago
Read 2 more answers
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