Refer to the diagram shown below.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
Answer:
375J of wasted energy
Explanation:
Efficiency=work output/work input×100%
50=w.o/750×100
750×50=100w.o
w.o=750×50/100
w.o=75×5
w.o=375J
Wasted energy=750J-375J
=375J
Aliter
If the machine is 50% efficient then it is also 50% inefficient
50%×750J=375J
Answer:
0.765m
Explanation:
gravitational potential energy GPE = mass * acceleration due to gravity * height
Given
GPE = 30Joules
Mass m = 4kg
acceleration = 9.8m/s²
Required
Height h
From the formula
h = GPE/mg
h = 30/4(9.8)
h = 30/39.2
h = 0.765m\
Hence the height of the counter is 0.765m
Virtual images are produced when rays of a light (after reflection or refraction) appear to meet a a certain point. While real images are produced when rays of a light (after reflection or refraction) meet at some point.
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