(7t-2) - (-3t+1) = -3*(1-3t)
First distribute:
7t-2+3t-1 = -3+9t
Now get all the terms with 't' on the same side by subtracting/adding:
7t+3t-9t = -3+2+1
Combine the terms:
1t=0
t=0
Check:
Plug in 0 for t and see if both sides of the equation come out the same:
Does (7(0)-2) - (-3(0)+1) = -3(1-3(0)) ?
(-2) - (1) = -3(1) ?
-3 = -3 ?
Yes! It works, so t=0!
Answer:
3(3x^2−y)(16x^2−27y)
Step-by-step explanation:
I used a website to get the answer.
Hey there, Lets solve this step by step.
<span>A number t divided by 82
</span>
Let the number be represented by y.
<span>t divided by 82 = t / 8
</span>
Therefore-
<span>In algebraic expressions, "y" is normally used as the dependent variable and "x" is normally used as the independent variable, instead of other variables. So that is why i used the variable y in the equation. </span>
Answer:
es 200
Step-by-step explanation:
100+100=200
0+0+0+0+0=0
<span>
<u><em>The correct answers are: </em></u>1) f(x)=1/2x;
2) f(x)=2x+1;
3) f(x)=x^3;
4) f(x)=6x.
<u><em>Explanation</em></u><span>
<u><em>: </em></u>Let x be the input. In function notation, the output is denoted by f(x).
For #1, since the output is half of the input, we want to take half of x; this would give us
f (x)=</span></span>

<span><span>x.
For #2, twice the input is 2x; one more than this is 2x+1, which gives us
f (x)=2x+1.
For #3, the cube of the input is x</span></span>³<span><span>, which gives us
f (x)=x</span></span>³<span><span>.
For #4, six times the input is 6x, which gives us
f (x)=6x.</span></span>