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3 years ago

A number greater than 40 and have 5 in the tenths place

Mathematics

2 answers:

Varvara68 [4.7K]3 years ago

7 0

A number greater than 40 and have 5 in the tenth place is 50

galina1969 [7]3 years ago

7 0

The real answer is 40.5-40.59 since it is in the tenths place

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One number is 9 more than 3 times another. If their difference is 29, what is the larger number?

vfiekz [6]

Answer:

Step-by-step explanation:

x-3y=9

x-y=29

subtract

-2y=-20

y=10

x-10=29

x=39

6 0

3 years ago

Read 2 more answers

5.69÷7 you can round to nearest hundredth

pogonyaev

The answer would be .81 becuase you can't round the 1 up to 2 becuase the number in the thousandths place is not above 5.
Hope this helps!!

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3 years ago

River C is 400 miles longer than River D. If the sum of their lengths is 5 comma 520 miles, what is the length of each river?

Viefleur [7K]

If the sum of their lengths is 5,520 miles then River D is 2360 and River C is 3160

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3 years ago

Is y = 0.860x + 3.302 a linear function?

gulaghasi [49]

Answer:

yes

Step-by-step explanation:

Yes. The given function has the form y = mx + b, which is that of a linear function. Here the slope, m, is 0.860, and the y-intercept is 3.302.

8 0

3 years ago

Plz guys help i need asap<br> its part b im stuck

aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

4 0

3 years ago