The horizontal component can be calculated using:
500cos(15)
= 483.0 meters
The answer is A.
It would be the first one
Answer: A
Step-by-step explanation: A because it corresponds to the other black dots but if you do B or C, it wouldn't work because it doesn't correspond to them.
Answer:
Allocation: 4 samples should be from the mountain and 16 from along the coast.
Step-by-step explanation:
Neyman allocation is technique of sample allocation used in cases of stratified sampling.
The formula to compute the best sample size of each stratum is:
![n_{h}=n\times \frac{(N_{h}\times SD_{h})}{\sum\limits^{k}_{i=1}(N_{i}\times SD_{i})}](https://tex.z-dn.net/?f=n_%7Bh%7D%3Dn%5Ctimes%20%5Cfrac%7B%28N_%7Bh%7D%5Ctimes%20SD_%7Bh%7D%29%7D%7B%5Csum%5Climits%5E%7Bk%7D_%7Bi%3D1%7D%28N_%7Bi%7D%5Ctimes%20SD_%7Bi%7D%29%7D)
The information provided is:
![N_{m}=50\\N_{c}=100\\n=20\\](https://tex.z-dn.net/?f=N_%7Bm%7D%3D50%5C%5CN_%7Bc%7D%3D100%5C%5Cn%3D20%5C%5C)
Compute the range for the number of people at the mountain campsite as follows:
![R_{m}=6-1=5](https://tex.z-dn.net/?f=R_%7Bm%7D%3D6-1%3D5)
Then the standard deviation for the number of people at the mountain campsite will be:
![SD_{m}=\frac{R_{m}}{4}=\frac{5}{4}](https://tex.z-dn.net/?f=SD_%7Bm%7D%3D%5Cfrac%7BR_%7Bm%7D%7D%7B4%7D%3D%5Cfrac%7B5%7D%7B4%7D)
Compute the range for the number of people along the coast campsite as follows:
![R_{c}=10-1=9](https://tex.z-dn.net/?f=R_%7Bc%7D%3D10-1%3D9)
Then the standard deviation for the number of people along the coast campsite will be:
![SD_{c}=\frac{R_{c}}{4}=\frac{9}{4}](https://tex.z-dn.net/?f=SD_%7Bc%7D%3D%5Cfrac%7BR_%7Bc%7D%7D%7B4%7D%3D%5Cfrac%7B9%7D%7B4%7D)
Compute the sample size for the mountain campsite as follows:
![n_{m}=n\times \frac{(N_{m}\times SD_{m})}{(N_{m}\times SD_{m})+(N_{c}\times SD_{c})}](https://tex.z-dn.net/?f=n_%7Bm%7D%3Dn%5Ctimes%20%5Cfrac%7B%28N_%7Bm%7D%5Ctimes%20SD_%7Bm%7D%29%7D%7B%28N_%7Bm%7D%5Ctimes%20SD_%7Bm%7D%29%2B%28N_%7Bc%7D%5Ctimes%20SD_%7Bc%7D%29%7D)
![=20\times \frac{(50\times (5/4))}{(50\times (5/4))+(100\times (9/4))}\\\\=20\times 0.2174\\\\=4.348\\\\\approx 4](https://tex.z-dn.net/?f=%3D20%5Ctimes%20%5Cfrac%7B%2850%5Ctimes%20%285%2F4%29%29%7D%7B%2850%5Ctimes%20%285%2F4%29%29%2B%28100%5Ctimes%20%289%2F4%29%29%7D%5C%5C%5C%5C%3D20%5Ctimes%200.2174%5C%5C%5C%5C%3D4.348%5C%5C%5C%5C%5Capprox%204)
Compute the sample size for along the coast campsite as follows:
![n_{c}=n-n_{m}=20-4=16](https://tex.z-dn.net/?f=n_%7Bc%7D%3Dn-n_%7Bm%7D%3D20-4%3D16)
Thus, 4 samples should be from the mountain and 16 from along the coast.
Answer: The answer would be letter A
slope (m)=-9/2
intercept on x-axis=56/9
intercept on y-axis=28
Explanation:
18x+4y=112
(18x)/112+(4y)/112=1
(x/1)/(56/9)+y/28=1
intercept on x-axis=56/9
intercept on y-axis=28
now, 4y=-18x+112
y=-9/2x+28
so, slope (m)=-9/2
Step-by-step explanation:
Move all terms that don't contain y to the right side and solve.
y
= 28 − (9
x)
/(2)