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Ipatiy [6.2K]
3 years ago
9

Use these four expressions to make a hypothesis about the closure property of interfere under each operation.

Mathematics
1 answer:
12345 [234]3 years ago
5 0

Answer: 1. Yes. 2. Yes. 3. Yes. 4. No

Step-by-step explanation:

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(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot
VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

a)

We could model this situation with a binomial distribution

P(6;k)=\binom{6}{k}p^kq^{6-k}

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

So

\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}

b)  

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}

P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281

P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484

P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438

P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109

P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781

and adding up these values we have that the probability that Y is less than 6 is

\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%

c)

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.  

In a binomial distribution, the standard deviation is  

s = \sqrt{npq}

In this case  

\sqrt{200(0.85)(0.15)}=5.05

<em>Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05</em>

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is  

0.0238 or 2.38%

d)<em> In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).</em>

In general, we can do this if the sample of size n the following inequalities hold:

np\geq 5 \;and\;nq \geq 5

in our case np = 200*0.85 = 170 and nq = 200*0.15 = 30

4 0
3 years ago
Which coordinate pair is the best estimate of the point of intersection in this graph? A. (1.5,0.75) B. (1.75,0.5) C. (0.75,1.5)
gladu [14]
Isn’t there posed to be a graph to show....
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B28%7D%7B40%7D" id="TexFormula1" title="\frac{28}{40}" alt="\frac{28}{40}" align="abs
Vitek1552 [10]

Answer:

7/10

Step-by-step explanation:

28/40=

14/20 =

7/10

8 0
3 years ago
Read 2 more answers
For an A.P. ,The first two term are -3, 4. The 21st term is
Dahasolnce [82]

Answer:

The 21st term is 137.

Step-by-step explanation:

Arithmetic progression:

In an arithmetic progression the difference between consecutive terms is always the same, and its called common difference.

The nth term is given by:

a_n = a_1 + (n-1)d

In which a_1 is the first term and d is the common difference.

The first two terms are -3, 4.

This means that a_1 = -3, d = 4 - (-3) = 7

So

a_n = a_1 + (n-1)d

a_n = -3 + 7(n-1)

The 21st term is

a_{21} = -3 + 7(21-1) = -3 + 140 = 137

The 21st term is 137.

4 0
3 years ago
PLZ HELP 20 POINTS AND CHOOSING BRAINLIEST
kow [346]
The answer is C (301.6)
8 0
3 years ago
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